A 2kgball rolls off a 30m-high cliff, and lands 25mfrom the base of the cliff. Express the displacement and the gravitational force in terms of vectors and calculate the work done by the gravitational force. Note that the gravitational force is (0,-mg,0), where g is a positive number+9.8N/kg.

Short Answer

Expert verified

The displacement and the gravitational force in terms of vector are 25i^-30j^ and -(19.6N)j^

respectively and the work done by the gravitational force is 588J

Step by step solution

01

Identification of the given data

The given data can be listed below as,

  • The mass of the ball is, 2kg.

  • The height of the cliff is, 30m.

  • The ball lands from the base of the cliff is, 25m.

  • The gravitational force is, (0,-mg,0).

02

Significance of law of conservation of energy for the ball

This law states that energy is neither created nor destroyed, it gets only converted to one form or another.

So, the work done will be equal to the product of the force applied and the displacement.

03

Determination of the gravitational force in terms of vector

Let +ybe the upward direction of the ball and+x direction is the landing area of the ball.

Height along the +x axis and also the role="math" localid="1657726786348" +y axis is 25m and 30m respectively.

So, the displacement of the ball in the vector form is expressed as,

d-25i^-30j^
04

Determination of the displacement in terms of vector

The gravitational force of the ball in terms of vector is expressed as,

F=-mgj^

Here, m is the mass of the ball and g is the acceleration due to gravity.

Substitute all the values in the above expression.

role="math" localid="1657727095174" F\mathscrF=-(2kg)(9.8N/kg)j^

=-(19.6N)j^

05

Determination of the work done by the gravitational force

From the law of conservation of energy, the work done by the gravitational force is as follows,

W=FA·d

Here,Fnis the gravitational force and dis the displacement of the ball.

Substituting all the values in the above equation.

W=-19.6N×j^×(-30m)j^

=588N·m×1J1N·m

=588J

The displacement and the gravitational force in terms of vector are 25i^-30j^ and -(19.6N)j¯ respectively and the work done by the gravitational force is 588J.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You bring a boat toward the dock by pulling on a rope with a force of130 N through a distance of 6 M . (a) How much work do you do? (Include the appropriate sign.) (b) Then you slow the boat down by pushing against it with a force of 40 N, opposite to the boat’s movement of. How much work do you do? (Include the appropriate sign.) (c) What is the total amount of work that you do?

Question: The radius of the Moon is 1750 km, and its mass is 7×1022kg. What would be the escape speed from an isolated Moon? Why was a small rocket adequate to lift the lunar astronauts back up from the surface of the Moon?

Question: An automobile traveling on a highway has an average kinetic energy of . Its mass is . What is its average speed? Convert your answer to miles per hour to see whether it makes sense. If you could use all of themc2rest energy of some amount of fuel to provide the car with its kinetic energy of , What mass of fuel would you need?

An automobile traveling on a highway has an average kinetic energy of . Its mass is . What is its average speed? Convert your answer to miles per hour to see whether it makes sense. If you could use all of themc2rest energy of some amount of fuel to provide the car with its kinetic energy of , What mass of fuel would you need?

You push a box out of a carpeted room and along a hallway with a waxed linoleum floor. While pushing the crate 2 mout of the room you exert a force of34N; while pushing italong the hallway you exert a force of40N. To slow it down you exert a force ofthrough a distance of2m, opposite to the motion. How much work do you do in all?

Answer

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free