A paper airplane flies from positionto. The net force acting on it during this flight, due to the Earth and the air, is nearly constant at.What is the total work done on paper airplane by the Earth and the air?

Work is the force times the displacement of the item and is the quantity of energy transferred between a source of applied force and the object that this force affects.

The work done as a result of the force is given by:

$W=\stackrel{\rightharpoonup }{F}∆\stackrel{\rightharpoonup }{r}cos\theta$

Here, F is the force, and$∆r$is the displacement, and$\theta$is the angle.

The applied force and displacement have the same angle$0°$, indicating that both elements move in the same direction.

Substitute$\theta =0°$ into the formula of work done.

$$\begin{gathered} W=F∆r\cos 0° \\ =F∆r \end{gathered}$$

The paper shifts its position. So, the displacement is given by:

$∆r=r_1=r_i$

Substitute the initial and the final position vector into the above formula to find the displacement.

Substitute and into$W=F∆r$ to find work done.

Hence, the total work done on the paper airplane by the Earth and the air is$1.4Nm.$