You throw a ball straight up, and it reaches a height of20 mabove your hand before falling back down. What was the speed of the ball just after it left your hand?

Short Answer

Expert verified

The speed of the ball just after it left at the hand was 19.8 m/s .

Step by step solution

01

Identification of the given data

The given data is listed as follows,

The height of the ball above the hand before falling back down is, h=20 m

02

Expression for the kinetic energy and the potential energy

The expression for the kinetic energy is as follows,

K.E=12mv2

Here,m is the mass, andvis the speed.

The expression for the potential energy is as follows,

P.E=mgh

Here, m is the mass, g is the acceleration due to gravity with value 93.8m/s2, and his the height of the object.

03

Determination of the speed of the ball

The initial and final energy of the ball is being conserved, so, the expression is as follows,

Ei=Ef12mv2=mghv=2gh

Substitute all the values in the above expression.

v=29.8m/s220m=19.8m/s

Thus, the speed of the ball just after it left the hand was 19.8m/s

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In each of the following cases state whether the work done by the specified force is positive, negative or zero. Also state whether the kinetic energy of the object in question increases, decreases or remains the same.

(a) A ball is moving upward, acted on by a downward gravitational force.

(b) A ball is falling downward, acted on by a downward gravitational force.

(c) A car is moving rapidly to the left and Superman exerts a force on it to the right to slow it down, backing up to the left as he pushes to the right.

(d) You throw a ball downward. Consider the force exerted by your hand on the ball while they are in contact.

(e) In a 6 month period the Earth travels halfway around its nearly circular orbit of the Sun. Consider the gravitational force exerted on the Earth by the Sun during this period.

The radius of Mars (from the center to just above the atmosphere) is (3400 km 3400×103m), and its mass is 0.6×1024kg . An object is launched straight up from just above the atmosphere of Mars. (a) What initial speed is needed so that when the object is far from Mars its final speed is 1000m/s? (b) What initial speed is needed so that when the object is far from Mars its final speed is 0m/s? (This is called the escape speed.)

A runner whose mass is 60kgruns in the +xdirection at a speed of 7m/s. (a) What is the kinetic energy of the runner? (b) Runner turns around and runs in the-xdirection at the same speed. Now what is the kinetic energy of the runner?

A comet is in elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4×1010m (inside the orbit of Mercury), at which point its speed is 8.17×104m/s. Its farthest distance from the Sun is far beyond the orbit of Pluto. What is its speed when it is 6×1012m from the Sun? (This is the approximate distance of Pluto from the Sun.)

You stand on a spherical asteroid of uniform density whose mass is 2×1016Kgand whose radius is 10Km. These are typical values for small asteroids, although some asteroids have been found to have much lower average density and are thought to be loose agglomerations of shattered rocks.

(a) How fast do you have to throw the rock so that it never comes back to the asteroid and ends up traveling at a speed of 3 m/swhen it is very far away?

(b) Sketch graphs of the kinetic energy of the rock, the gravitational potential energy of the rock plus asteroid, and their sum, as a function of separation (distance from centre of asteroid to rock).

Label the graphs clearly. The asteroid, and their sum, as a function of separation (distance from centre of asteroid to rock).

Label the graphs clearly.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free