In the preceding example, what fraction of the original neutron’s rest energy was converted into kinetic energy?

Kinetic energy is the type of energy that an item or particle has as a result of its movement. When work is done on an object by exerting a net force, the object accelerates and gains kinetic energy as a result.

Kinetic energy is a property of a moving item or particle that is determined by its mass as well as its motion.

The neutron's initial rest energy is expressed as follows,

$m_N{c}^2=939.6\mathrm{MeV}$

From the example, the transformed kinetic energy of the three particles is expressed as follows,

$$\begin{gathered} K_t=K_p+K_e+K_v \\ =0.8\mathrm{MeV} \end{gathered}$$

Divide the transformed kinetic energy by the neutron's initial rest energy.

$$\begin{gathered} \frac{K_t}{m_N{c}^2}=\frac{0.8MeV}{939.6\mathrm{MeV}} \\ =8.51\times {10}^{-4} \end{gathered}$$

Thus, the fraction of the original neutron's rest energy that was converted into kinetic energy is$8.51\times {10}^{-4}$ .