On a straight road with the +x axis chosen to point in the direction of motion, you drive for 3 h at a constant 30 mi/h, then in a few seconds you speed up to 60mi/h and drive at this speed for 1 h.

(a) What was the x component of average velocity for the 4 h period, using the fundamental definition. Of average velocity, which is the displacement divided by the time interval?

(b) Suppose that instead you use the equation vavg,x=(vix+vfx)2. What do you calculate for the x component of average velocity?

(c) Why does the equation used in part (b) give the wrong answer?

Short Answer

Expert verified
  1. Average velocityvavg=37.5 m/s
  2. The value of average velocity is vavg,x=45  mi/h
  3. Because the formula is valid for the constant rate.

Step by step solution

01

Identification of given data

  • Initial velocityvi=30 mi/h
  • Final velocity vf=60 mi/h
  • Initial timet1=3 h
  • Final time t2=1 h
02

 Average velocity

Average speed is the ratio of distance covered in a particular period of time.

03

 Calculation for the average velocity

(a)

The average speed of an object is calculated by

vavg=dtt

Here, dt- Total distance, and t -Total time

Distance travel in first 3h

d1=30×3d1=90 m

Distance travel in 1h

d2=60×1d2=60 mi

Total distance

dt=60+90dt=150 mi

Now,

vavg=1504vavg=37.5 mi/s

The value of average velocity is37.5 mi/s

04

 Calculation for the average velocity

(b)

The given equation from the question

vavg,x=vix+vfx2vavg,x=30+602vavg,x=45  mi/h

The value of average velocity isvavg,x=45  mi/h

05

 Explanation

(c)

The given formula in the question is being only valid for a constant rate like baseballs, which means the result generated is wrong. It didn’t consider the different time intervals.

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