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Chapter 2: Q.41P (page 45)

To get total internal reflection at the interface of water (refractive index 1.33) and a plastic whose refractive index is 1.46: (a) Which material must the light start in? (1) It doesn’t matter, (2) Water, (3) Plastic, (b) What is the critical angle?

Short Answer

Expert verified

Therefore, the correct option is (3): plastic

Step by step solution

01

Write the given data from the question.

Refractive index of water,n2=1.33

Refractive index of plastic,n1=1.46

02

Determine the relation to that relates the refractive index of water and plastic.

The expression that relates the refractive index of two medium: the Snell’s law is given as follows.

n1sinθ1=n2sinθ2 …… (i)

Here, θ2is the angle of refection and localid="1668593025790" θ1is the angle of incident.

03

Find out which material must the light start in.

To get the total internal reflection, the must travel from the denser medium to rarer medium and the angle of the incident in the denser medium must be greater than critical angle.

The refractive index of plastic is more than the refractive index of water. Therefore,

n1>n2

Hence the light starts from the plastic.

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