A proton has mass1.7×10-27kg. What is the magnitude of the impulse required to increase its speed from 0.990c to 0.994c?

Short Answer

Expert verified

The magnitude of the impulse required to increase its speed from 0.990c to 0.994c is 2.004×10-21Ns.

Step by step solution

01

Identification of the given data

  • The mass of a proton is 1.7×10-27kg.
  • The initial speed of a proton is 0.990c
  • The final speed of a proton is 0.994c
02

Definition of Impulse

m,mass of the proton=1.7×10-27kgv,final velocity=0.994c=0.994×3×108=2.982×108 m/su,initial velocity=0.990c=0.990×3×108=2.97×108 m/s

Impulse is the equivalent to the force as the change in momentum,

Impulse=mvmu(1)

Substitute these values in Equation (1),

localid="1657118294846" Impluse=1.67×10-27 kg×2.982×108 m/s1.67×10-27 kg×2.97×108 m/s=1.67×10-27×2.982×1081.67×10-27×2.97×1081 kg1 m1 s=2.004×10-21Ns

Hence,the magnitude of the impulse required to increase its speed from 0.990c to 0.994c is 2.004×10-21Ns.

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