In the circuit shown in Figure 19.75, the emf of the battery is 7.9V. Resistor R1 has a resistance of 23Ω , and resistor R2 has a resistance of 44Ω . A steady current flows through the circuit. (a) What is the absolute value of the potential difference across R1? (b) What is the conventional current through R2?

Short Answer

Expert verified

VR1=2.71V

Step by step solution

01

Given Data

emf=7.9VR1=23ΩR2=44Ω

02

Concept

If the current flows through the source of the negative terminal, then it is known as the conventional current.

03

Step 3(a): Determine the absolute value of the potential difference across R1

First we have to find the current,

l=emfR1+R2=7.923+44=0.1179Ω

The potential difference,

VR1=IR1=0.1179×23=2.71V

Hence, the absolute value of the potential difference across resistor 1 is 2.71 V

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