Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 2: Q56P-a (page 45)

In the circuit shown in Figure 19.77 the emf of the battery is 7.4V. Resistor R1has a resistance of 31Ω, resistor R2 has a resistance of 47Ω, and resistor localid="1662203602529" R3has a resistance of localid="1662203617219" 52Ω. A steady current flows through the circuit.

(a)What is the equivalent resistance of R1andR2 ? (b) What is the equivalent resistance of all three resistors? (c) What is the conventional current throughR3

Short Answer

Expert verified

18.68Ω

Step by step solution

01

Given Data

R1=31ΩR2=47ΩR3=52Ωemf=7.4V

02

Concept

The equivalent resistance is the addition of the resistances, when the batteries are connected in series.

03

Step 3(a): Determine the equivalent resistance of  R1 and R2

The resistors R1 and R2are connected in parallel, then the equivalent resistance,

Req=1R1+1R2=131+147=0.05ΩR4=1/0.05=18.68Ω

Hence, the equivalent resistance is 18.68Ω18.68Ω

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

As shown in Figure 19.74, a spherical metal shell of radius r1has a charge Q(on its surface) and is surrounded by a concentric spherical metal shell of radius r2which has a charge -Q(on its inner surface).

(a) Use the definition of capacitance: Q=C|△V|to find the capacitance of this spherical capacitor.

(b) If the radii of the spherical shells r1and r2are large and nearly equal to each other, show that Ccan be written as ε0As(which is also the equation for the capacitance of a parallel-plate capacitor) where A=4πr2is the surface area of one of the spheres, and sis the small gap distance between them r2=r1+s.

On a straight road with the +x axis chosen to point in the direction of motion, you drive for 3 h at a constant 30 mi/h, then in a few seconds you speed up to 60mi/h and drive at this speed for 1 h.

(a) What was the x component of average velocity for the 4 h period, using the fundamental definition. Of average velocity, which is the displacement divided by the time interval?

(b) Suppose that instead you use the equation vavg,x=(vix+vfx)2. What do you calculate for the x component of average velocity?

(c) Why does the equation used in part (b) give the wrong answer?

Figure 16.60 shows a portion of a long, negatively charged rod. You need to calculate the potential difference VD-Vc.

(a) What is the direction of the path (+yor-y)?

(b) What is the sign ofVA-VB?

(1)You push on a spring whose stiffness is 11 N/m, compressing it until it is 2.5 cm shorter than its relaxed length. What is the magnitude of the force the spring now exerts on your hand?

(2) A different spring is 0.17 m long when it is relaxed.

(a) When a force of magnitude 250 N is applied, the spring becomes 0.24 m long. What is the stiffness of this spring?

(b) This spring is compressed so that length is 0.15 m. What magnitude of the force is required to do this?

In gold at room temperature, the mobility of mobile electrons is about 4.3×10-3(msVm), and there are about 5.9×1028mobile electrons per cubic meter. Calculate the conductivity of gold, including correct units.

See all solutions

Recommended explanations on Physics Textbooks

Magnetism and Electromagnetic Induction

Read Explanation

Electricity and Magnetism

Read Explanation

Fundamentals of Physics

Read Explanation

Famous Physicists

Read Explanation

Measurements

Read Explanation

Translational Dynamics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free