Question:A system is acted upon by two forces,18,47,-23Nand-20,-13,41N. What is the net force acting on the system?

Short Answer

Expert verified

The net force acting on the system is-2,34,18N

Step by step solution

01

Understanding the definition of the net force

A force is described as a push or pull on an object that occurs due to the interaction of one system with a different system. When two items interact, each of them experiences a force.

02

Calculation for the net force

To calculate the net force acting on this system, combine all forces.

Add both the given forces as

FnetF1+F2

Substitute the values in the above expression.

Fnet=18,47,-23N+-20,-13,41N=-2,34,18N

Therefore, the net force acting on the system is-2,34,18N

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Most popular questions from this chapter

An object is moving in the + ydirection. Which. If any, of the following statements might be true? Check all that apply. a) the net force on the object is zero. b) The net force on the object is in the - ydirection. c) the net force on the object is in the + ydirection.

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(a.) If the disk was initially at rest, now how fast is it rotating? (b) What is the change in the kinetic energy of the child plus the disk? (c) where has most of this kinetic energy gone? (d) Calculate the change in linear momentum of the system consisting of the child plus the disk (but not including the axle), from just before to just after impact. What caused this change in the linear momentum? (e) The child on the disk walks inward on the disk and ends up standing at a new location a distance from the axle. Now what is the angular speed? (f) What is the change in the kinetic energy of the child plus the disk, from the beginning to the end of the walk on the disk? (g) What was the source of this increased kinetic energy?

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You may have noticed that while discharging a capacitor through a light bulb, the light glows just about as brightly, and for just about as long, as it does while charging the same capacitor through the same bulb. Let Estand for the energy emitted by the light bulb (as light and heat) in the discharging phase, from just before the bulb is connected to the capacitor until the time when there is essentially no more current. In terms of +Eor -E, what was the energy change of the battery, capacitor, bulb, and surroundings during the charging phase, and during the discharging phase? One answer is already given in the following table:

It is somewhat surprising that we can get this much information out of one simple observation.

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