Chapter 1: Problem 8
By how much does the pressure in a cylindrical jet of water \(4 \mathrm{~mm}\) in diameter exceed the pressure of the surrounding atmosphere if the surface tension of water is \(0.073 \mathrm{~N} \cdot \mathrm{m}^{-1}\) ?
Short Answer
Expert verified
The pressure in the cylindrical jet exceeds the atmospheric pressure by \(73 \; \text{kPa}\).
Step by step solution
01
Identify the Known Values
Extract the given information from the problem: - Diameter of the cylindrical jet, \(d = 4 \; \text{mm} = 4 \times 10^{-3} \; \text{m}\)- Surface tension of water, \(\gamma = 0.073 \; \text{N} \cdot \text{m}^{-1}\)
02
Calculate the Radius
Convert the diameter to radius by dividing by 2:\[ r = \frac{d}{2} = \frac{4 \times 10^{-3}}{2} = 2 \times 10^{-3} \; \text{m} \]
03
Use the Pressure Difference Formula
For a cylindrical jet of radius \(r\), the pressure difference due to surface tension is given by: \[ \Delta P = \frac{2 \gamma}{r} \]
04
Substitute the Known Values
Plug in the values for surface tension and radius: \[ \Delta P = \frac{2 \times 0.073}{2 \times 10^{-3}} \ \mathrm{N/m^2} \]
05
Calculate the Pressure Difference
Perform the calculation: \[ \Delta P = \frac{0.146}{2 \times 10^{-3}} = 73 \; \text{kPa} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
surface tension
Surface tension is an essential concept in fluid mechanics. It describes how the surface of a liquid acts like a thin elastic sheet. This happens because the molecules on the surface are pulled inward by cohesive forces from the molecules within the liquid. The result is that the liquid minimizes its surface area, leading to the formation of droplets and other phenomena.
Think of it like a stretched rubber band. It wants to shrink and pull inward, creating tension on the surface.
Surface tension has practical applications such as in detergents that lower water's surface tension for better cleaning. The force of surface tension is critical in calculating pressure differences in fluid systems.
Think of it like a stretched rubber band. It wants to shrink and pull inward, creating tension on the surface.
Surface tension has practical applications such as in detergents that lower water's surface tension for better cleaning. The force of surface tension is critical in calculating pressure differences in fluid systems.
cylindrical jet
In fluid dynamics, a cylindrical jet refers to a stream or flow of fluid that maintains a cylindrical shape as it moves. Examples include water coming out of a faucet or ink from a pen.
The dynamics of a cylindrical jet can differ significantly based on factors such as viscosity, velocity, and surface tension. Understanding these elements is crucial for calculating pressure differences within the jet.
In our problem, the cylindrical jet of water has a diameter of 4 mm. By converting it to radius (2 mm), we can use it to determine the pressure difference caused by surface tension.
The dynamics of a cylindrical jet can differ significantly based on factors such as viscosity, velocity, and surface tension. Understanding these elements is crucial for calculating pressure differences within the jet.
In our problem, the cylindrical jet of water has a diameter of 4 mm. By converting it to radius (2 mm), we can use it to determine the pressure difference caused by surface tension.
pressure calculation
Pressure calculation is a fundamental part of fluid mechanics that helps understand how forces are distributed within a fluid system. In our problem, we need to find the pressure difference between the inside of the cylindrical jet of water and the surrounding atmosphere.
We use the formula for pressure difference due to surface tension, which is \[ \Delta P = \frac{2 \gamma}{r} \]. This formula tells us that the pressure difference \(\Delta P \) is directly proportional to the surface tension \(\gamma \) and inversely proportional to the radius of the jet \(r \).
By substituting the known values into this formula, we can calculate that the pressure difference is 73 kPa. This information is vital in applications such as fluid transport systems and medical devices.
We use the formula for pressure difference due to surface tension, which is \[ \Delta P = \frac{2 \gamma}{r} \]. This formula tells us that the pressure difference \(\Delta P \) is directly proportional to the surface tension \(\gamma \) and inversely proportional to the radius of the jet \(r \).
By substituting the known values into this formula, we can calculate that the pressure difference is 73 kPa. This information is vital in applications such as fluid transport systems and medical devices.
fluid dynamics
Fluid dynamics is a branch of physics concerned with the movement of fluids (liquids and gases). It involves the study of the forces and energy that influence fluid motion and behavior.
Key principles in fluid dynamics include Bernoulli's principle, the continuity equation, and the Navier-Stokes equations. Each of these helps explain various fluid behaviors, from simple flows to complex turbulent patterns.
Our problem’s context involves understanding how surface tension and pressure differences play roles in the behavior of a cylindrical jet of water. By applying the principles of fluid dynamics, we can predict and control the flow of fluids in various engineering and scientific applications.
Key principles in fluid dynamics include Bernoulli's principle, the continuity equation, and the Navier-Stokes equations. Each of these helps explain various fluid behaviors, from simple flows to complex turbulent patterns.
Our problem’s context involves understanding how surface tension and pressure differences play roles in the behavior of a cylindrical jet of water. By applying the principles of fluid dynamics, we can predict and control the flow of fluids in various engineering and scientific applications.
- Bernoulli's principle links the speed of the fluid to its pressure.
- The continuity equation ensures the conservation of mass in fluid flow.
- Navier-Stokes equations describe the motion of viscous fluid substances.