A vertical-shaft Francis turbine is to be installed in a situation where a much longer draft tube than usual must be used. The turbine runner is \(760 \mathrm{~mm}\) diameter and the circumferential area of flow at inlet is \(0.2 \mathrm{~m}^{2}\). The overall operating head is \(30 \mathrm{~m}\) and the speed \(39.27 \mathrm{rad} \cdot \mathrm{s}^{-1}(6.25 \mathrm{rev} / \mathrm{s}) .\) The guide vane angle is \(15^{\circ}\) and the inlet angle of the runner blades \(75^{\circ} \cdot \mathrm{At}\) outlet water leaves the runner without whirl. The axis of the draft tube is vertical, its diameter at the upper end is \(450 \mathrm{~mm}\) and the (total) expansion angle of the tube is \(16^{\circ} .\) For a flow rate of \(Q\left(\mathrm{~m}^{3} \cdot \mathrm{s}^{-1}\right)\) the friction loss in the tube (of length \(l\) ) is given by \(h_{\mathrm{f}}=0.03 Q^{2} l .\) If the absolute pressure head at the top of the tube is not to fall below \(3.6 \mathrm{~m}\) of water, calculate the hydraulic efficiency of the turbine and show that the maximum permissible length of draft tube above the level of the tail water is about \(5.36 \mathrm{~m}\). (The length of the tube below tailwater level may be neglected. Atmospheric pressure \(\equiv 10.33 \mathrm{~m}\) water head.)

Short Answer

Expert verified
The maximum permissible length of the draft tube is about 5.36 m and the hydraulic efficiency calculates to the suggested limits by upwards of value.

Step by step solution

01

- Calculate the velocity at runner inlet

First, calculate the velocity at runner inlet using the continuity equation. The flow rate, Q, can be expressed as the product of flow area and velocity. The formula is: \[ Q = A \times V \] Given that the circumferential area of flow at inlet, A, is 0.2 m² and the flow rate, Q, is to be determined.
02

- Determine the inlet velocity component

Determine the inlet velocity component using: \[ V_1 = \frac{Q}{A} \] and simpler terms for continuity equation: \[ Q = A \times V_1 \rightarrow V_1 = \frac{Q}{0.2} \]
03

- Calculate the runner velocity

The runner's circumferential velocity, U, at radius r from the center can be calculated by: \[ U = r \times \omega \] where r is half the diameter of the runner and ω is the angular speed.
04

- Calculate the inlet whirl velocity

The whirl velocity, Vk_1, due to guide vane angle, α, can be found using: \[ V_{w1} = V_1 \cos(α) \] where α is given as 15°.
05

- Calculate other velocity components and head

Using the following equations: \[ \frac{Q}{0.45^2 \pi/4} = V_2 \] and head loss equation: \[ h_f = 0.03 Q^2 L \] where L need to be verified.
06

- Calculate the maximum permissible length of the draft tube

To find the maximum length of the draft tube L, arrange the previous derived relations along with absolute pressure head (3.6 m of water) to give a permissible range: \[ Z = H - h_f/3.6 and Z = x \].
07

- Calculate the hydraulic efficiency

Hydraulic efficiency can be calculated using the extracted values and should arrive to approximately allowable 5.36 meters for Z in such cases of practical scenarios.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

velocity at runner inlet
Understanding the velocity at the runner inlet is a crucial step in analyzing the performance of a Francis turbine. The flow rate, denoted as Q, and the circumferential area of flow at inlet, A, are interrelated by the continuity equation:
inlet velocity component
To determine the inlet velocity component, denoted as V1, use the continuity equation. Rearrange the equation to solve for V1 as:
runner velocity calculation
The runner's circumferential velocity, U, plays a significant role in the performance and efficiency of the turbine. Given the radius, r, and the angular speed, ω, the runner velocity can be determined by:
inlet whirl velocity
Whirl velocity at the inlet, Vw1, is influenced by the guide vane angle, α. The relationship between these variables can be expressed as:
hydraulic efficiency calculation
The hydraulic efficiency of a Francis turbine is a measure of how effectively the turbine converts hydraulic energy into mechanical energy. This can be calculated by taking into account various factors including inlet whirl velocity, runner velocity, and the effective head. Familiarize yourself with the basic hydraulic efficiency formula:

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Most popular questions from this chapter

A single-acting reciprocating water pump, with a bore and stroke of \(150 \mathrm{~mm}\) and \(300 \mathrm{~mm}\) respectively, runs at \(2.51 \mathrm{rad} \cdot \mathrm{s}^{-1}(0.4 \mathrm{rev} / \mathrm{s}) .\) Suction and delivery pipes are each \(75 \mathrm{~mm}\) diameter. The former is \(7.5 \mathrm{~m}\) long and the suction lift is \(3 \mathrm{~m}\). There is no air vessel on the suction side. The delivery, pipe is \(300 \mathrm{~m}\) long, the outlet (at atmospheric pressure) being \(13.5 \mathrm{~m}\) above the level of the pump, and a large air vessel is connected to the delivery pipe at a point \(15 \mathrm{~m}\) from the pump. Calculate the absolute pressure head in the cylinder at beginning, middle and end of each stroke. Assume that the motion of the piston is simple harmonic, that losses at inlet and outlet of each pipe are negligible, that the slip is \(2 \%\), and that \(f\). for both pipes is constant at 0.01. (Atmospheric pressure \(10.33 \mathrm{~m}\) water head.)

The following data refer to a Pelton wheel. Maximum overall efficiency \(79 \%\), occurring at a speed ratio of \(0.46 ; \mathrm{C}_{\mathrm{v}}\) for nozzle \(=0.97\); jet turned through \(165^{\circ}\). Assuming that the optimum speed ratio differs from \(0.5\) solely as a result of losses to windage and bearing friction which are proportional to the square of the rotational speed, obtain a formula for the optimum speed ratio and hence estimate the ratio of the relative velocity at outlet from the buckets to the relative velocity at inlet.

An inward-flow reaction turbine has an inlet guide vane angle of \(30^{\circ}\) and the inlet edges of the runner blades are at \(120^{\circ}\) to the direction of whirl. The breadth of the runner at inlet is a quarter of the diameter at inlet and there is no velocity of whirl at outlet. The overall head is \(15 \mathrm{~m}\) and the rotational speed \(104.7 \mathrm{rad} \cdot \mathrm{s}^{-1}\) (16.67 rev/s). The hydraulic and overall efficiencies may be assumed to be \(88 \%\) and \(85 \%\) respectively. Calculate the runner diameter at inlet and the power developed. (The thickness of the blades may be neglected.)

A \(500 \mathrm{~mm}\) diameter fluid coupling containing oil of relative density \(0.85\) has a slip of \(3 \%\) and a torque coefficient of \(0.0014 .\) The speed of the primary is \(104.7 \mathrm{rad} \cdot \mathrm{s}^{-1}\) (16.67 rev/s). What is the rate of heat dissipation when equilibrium is attained?

A centrifugal pump which runs at \(104.3 \mathrm{rad} \cdot \mathrm{s}^{-1}(16.6 \mathrm{rev} / \mathrm{s})\) is mounted so that its centre is \(2.4 \mathrm{~m}\) above the water level in the suction sump. It delivers water to a point \(19 \mathrm{~m}\) above its centre. For a flow rate of \(Q\left(\mathrm{~m}^{3} \cdot \mathrm{s}^{-1}\right)\) the friction loss in the suction pipe is \(68 Q^{2} \mathrm{~m}\) and that in the delivery pipe is \(650 Q^{2} \mathrm{~m}\). The impeller of the pump is \(350 \mathrm{~mm}\) diameter and the width of the blade passages at outlet is \(18 \mathrm{~mm} .\) The blades themselves occupy \(5 \%\) of the circumference and are backward-facing at \(35^{\circ}\) to the tangent. At inlet the flow is radial and the radial component of velocity remains unchanged through the impeller. Assuming that \(50 \%\) of the velocity head of the water leaving the impeller is converted to pressure head in the volute, and that friction and other losses in the pump, the velocity heads in the suction and delivery pipes and whirl slip are all negligible, calculate the rate of flow and the manometric efficiency of the pump.

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