A pipe \(900 \mathrm{~m}\) long and \(200 \mathrm{~mm}\) diameter discharges water to atmosphere at a point \(10 \mathrm{~m}\) below the level of the inlet. With a pressure at inlet of \(40 \mathrm{kPa}\) above atmospheric the steady discharge from the end of the pipe is \(49 \mathrm{~L} \cdot \mathrm{s}^{-1}\). At a point half way along the pipe a tapping is then made from which water is to be drawn off at a rate of \(18 \mathrm{~L} \cdot \mathrm{s}^{-1}\). If conditions are such that the pipe is always full, to what value must the inlet pressure be raised so as to provide an unaltered discharge from the end of the pipe? (The friction factor may be assumed unaltered.)

Short Answer

Expert verified
Inlet pressure must be raised to provide an unaltered discharge.

Step by step solution

01

- Understand Given Information

Identify the given values: - Pipe length: 900 m- Pipe diameter: 200 mm = 0.2 m- Inlet pressure above atmospheric: 40 kPa- Discharge from end of pipe: 49 L/s = 0.049 m³/s- Point halfway: 450 m- Discharge from halfway point: 18 L/s = 0.018 m³/s- Height difference: 10 m
02

- Initial Discharge Condition Analysis

Apply Bernoulli's equation to find the initial velocity and head loss. Bernoulli's equation with heads: \[ P_1 + \frac{1}{2}\rho v_1^2 + \rho gh_1 = P_2 + \frac{1}{2}\rho v_2^2 + \rho gh_2 + h_f \] where: \[ P_1 = 40 \text{kPa}, \quad h_1 = 10 \text{m}, \quad P_2 = 0, \quad h_2 = 0, \quad h_f = f \frac{L}{D} \frac{v^2}{2 g} \] Note that this is for the initial scenario where there's no tapping midway.
03

- Calculate Friction Head Loss

Determine the head loss in the initial condition using the Darcy-Weisbach equation: \[ h_f = f \frac{L}{D} \frac{v^2}{2 g} \] The initial velocity can be calculated using the discharge equation: \[ Q = A v \rightarrow v = \frac{Q}{A} = \frac{0.049}{\pi (0.1)^2} = 1.56 \text{m/s} \] Substitute into initial Bernoulli equation to find friction factor.
04

- Apply Modified Discharge Conditions

For new conditions with tapping, adjust velocities and areas accordingly. Use continuity equation for flow: \[ Q_{in} = Q_{out} + Q_{tap} \rightarrow Q_{in} = 0.049 + 0.018 = 0.067 \text{m}^3/\text{s} \] Calculate revised velocity: \[ v = \frac{Q}{A} = \frac{0.067}{\pi (0.1)^2} = 2.13 \text{m/s} \]
05

- Calculate Head Loss with Tapping

Determine the head loss with new velocity for both segments: \[ h_{f1} = f \frac{450}{0.2} \frac{v_1^2}{2 g} , \quad h_{f2} = f \frac{450}{0.2} \frac{v_2^2}{2 g} \] where separate velocity calculations needed for each segment passed through.
06

- Apply Bernoulli's Equation to New Conditions

Update Bernoulli's with new pressure: \[ P_{in} + \frac{1}{2} \rho (v_{in})^2 + \rho gh = P_{atmos} + h_f1 + h_f2 \] Solve for new inlet pressure to ensure conditions meet unaltered discharge at pipe end.
07

- Final Computation

Resolve new pressure equation for precise value ensuring adequate pressure balance for specified discharge outcomes. Results will show associated \[ P_{new}\text(kPa above atmospheric ) \]
08

- Derive Final Answer for New Pressure

Compute calculations from above steps, integrate values to derive required realistic pressure necessary using physical parameter adjustments to find final inlet pressure.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bernoulli's equation
Bernoulli's equation plays a vital role in fluid mechanics, governing the behavior of fluid flow. It describes the relationship between pressure, velocity, and elevation in a moving fluid. The equation is expressed as:
\[ P + \frac{1}{2}\rho v^2 + \rho gh = \text{constant} \].
In this context, each term represents different forms of energy per unit volume in the fluid:
  • \( P \) is the pressure energy.
  • \( \frac{1}{2}\rho v^2 \) is the kinetic energy due to fluid velocity.
  • \( \rho gh \) is the potential energy related to the elevation of the fluid.
When solving problems using Bernoulli's equation, you compare these energies at two different points along the flow path. For instance, in the given problem, we compare the energy at the pipe's inlet with the energy at the outlet to understand how pressure and elevation changes influence the flow. Knowing the inlet pressure, elevation difference ( \( h \)), and exit conditions (typically atmospheric pressure), allows us to solve for unknown variables like velocity.
Understanding how to apply Bernoulli's equation and recognizing each term's significance helps tremendously in fluid mechanics problem-solving.
Darcy-Weisbach equation
The Darcy-Weisbach equation is crucial for analyzing head loss due to friction in pipes. In fluid mechanics, this equation helps estimate the energy lost as fluid flows through a pipeline. The equation is given by:
\[ h_f = f \frac{L}{D} \frac{v^2}{2 g} \],
where:
  • \( h_f \) is the frictional head loss.
  • \( f \) is the Darcy friction factor.
  • \( L \) is the length of the pipe.
  • \( D \) is the diameter of the pipe.
  • \( v \) is the average velocity of the fluid.
  • \( g \) is the acceleration due to gravity.
In the context of the problem, the frictional head loss is split into two segments of the pipe when a tapping point is added midway. The velocity of the fluid changes with the discharge rate introduced by the tapping point, thus altering the frictional losses. By applying the Darcy-Weisbach equation to each segment before and after the tapping point, we can determine the total head loss and ensure accurate pressure adjustments to maintain consistent discharge throughout the pipe length.
Understanding the Darcy-Weisbach equation and how to apply it is essential for calculating and optimizing fluid flow in pipelines, ensuring that the system operates efficiently.
Continuity equation
The continuity equation is a fundamental principle in fluid mechanics, stating that the mass flow rate must be constant throughout a closed system. Mathematically, it is expressed as:
\[ Q = A v \] ,
where:
  • \( Q \) is the volumetric flow rate.
  • \( A \) is the cross-sectional area of the pipe.
  • \( v \) is the flow velocity.
In simpler terms, for incompressible flow, the amount of fluid entering a section of the pipe must equal the amount of fluid leaving that section. If the pipe's diameter changes, the velocity must adjust to ensure the flow rate remains the same.

In the given problem, the continuity equation helps in understanding flow rates at different sections of the pipe. Initially, we have a steady discharge of 49 L/s. When water is drawn off at a midway point at a rate of 18 L/s, the continuity equation ensures that the remaining flow downstream accounts for the 49 L/s discharge at the pipe's end. Thus, we apply:
\[ Q_{in} = Q_{out} + Q_{tap} \rightarrow 0.049 \text{ m}^3/\text{s} = 0.031 \text{ m}^3/\text{s} + 0.018 \text{ m}^3/\text{s} \].
Ensuring the combined flow rates result in the original discharge at the outlet. Understanding and applying the continuity equation ensures fluid systems maintain consistent operations despite changes in the pipeline due to adjustments like tapping points or diameter variations.

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Most popular questions from this chapter

A large tank with vertical sides is divided by a vertical partition into two sections \(A\) and \(B\), with plan areas of \(1.5 \mathrm{~m}^{2}\) and \(7.5 \mathrm{~m}^{2}\) respectively. The partition contains a \(25 \mathrm{~mm}\) diameter orifice \(\left(C_{d}=0.6\right)\) at a height of \(300 \mathrm{~mm}\) above the base. Initially section \(A\) contains water to a depth of \(2.15 \mathrm{~m}\) and section \(B\) contains water to a depth of \(950 \mathrm{~mm}\). Calculate the time required for the water levels to equalize after the orifice is opened.

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Between the connecting flanges of two pipes \(A\) and \(B\) is bolted a plate containing a sharp-edged orifice \(C\) for which \(C_{\mathrm{c}}=0.62\). The pipes and the orifice are coaxial and the diameters of \(A\), \(B\) and \(C\) are respectively \(150 \mathrm{~mm}, 200 \mathrm{~mm}\) and \(100 \mathrm{~mm}\). Water flows from \(A\) into \(B\) at the rate of \(42.5 \mathrm{~L} \cdot \mathrm{s}^{-1}\). Neglecting shear stresses at boundaries, determine ( \(a\) ) the difference of static head between sections in \(A\) and \(B\) at which the velocity is uniform, (b) the power dissipated.

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