Chapter 2: Problem 11
Tau-leptons are produced in the process \(\mathrm{e}^{+} \mathrm{e}^{-} \rightarrow \tau^{+} \tau^{-}\)at a centre-of-mass energy of \(91.2 \mathrm{GeV}\). The angular distribution of the \(\pi^{-}\)from the decay \(\tau^{-} \rightarrow \pi^{-} v_{\tau}\) is $$ \frac{\mathrm{d} N}{\mathrm{~d}\left(\cos \theta^{*}\right)} \propto 1+\cos \theta^{*} $$ where \(\theta^{*}\) is the polar angle of the \(\pi^{-}\)in the tau-lepton rest frame, relative to the direction defined by the \(\tau(\) tau \()\) spin. Determine the laboratory frame energy distribution of the \(\pi^{-}\)for the cases where the tau-lepton spin is (i) aligned with or (ii) opposite to its direction of flight.
Short Answer
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Key Concepts
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