At the HERA collider, \(27.5 \mathrm{GeV}\) electrons were collided head-on with \(820 \mathrm{GeV}\) protons. Calculate the centre-ofmass energy.

Short Answer

Expert verified
The center-of-mass energy is approximately \(212.33\) GeV.

Step by step solution

01

- Understand the Formula for Center-of-Mass Energy

The center-of-mass energy (\text{E}_{\text{CM}}) for a collision involving two particles can be calculated using the formula:\[E_{\text{CM}} = \sqrt{2E_{1}E_{2} \left(1 + \frac{1}{c^2}\right)}\]where \(E_{1}\) and \(E_{2}\) are the energies of the two particles and \(c\) is the speed of light. For relativistic particles where energy is significantly larger than the rest mass, this formula simplifies to:\[E_{\text{CM}} \approx \sqrt{2E_{1}E_{2}}\]
02

- Identify Given Values

From the exercise, the energies of the electrons (\(E_{1}\)) and protons (\(E_{2}\)) are given as: \(E_{1} = 27.5 \ \mathrm{GeV}\) and \(E_{2} = 820 \ \mathrm{GeV}\).
03

- Substitute the Values into the Formula

Using the simplified formula for highly relativistic collisions:\[E_{\text{CM}} \approx \sqrt{2 \times 27.5 \times 820 \ \mathrm{GeV}^2}\]
04

- Calculate the Center-of-Mass Energy

First, calculate the product:\[2 \cdot 27.5 \cdot 820 = 45100 \ \mathrm{GeV}^2\]Now, take the square root of the product:\[E_{\text{CM}} = \sqrt{45100} \ \approx 212.33 \ \mathrm{GeV}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relativistic Particle Collisions
In the world of particle physics, particles often move at speeds close to the speed of light. These are called relativistic particles. When such particles collide, the energy involved is immense. Understanding how to calculate this energy is crucial.

Relativistic collisions take into account not just the speed but also the mass and energy of the particles involved. A special formula helps us find something called the center-of-mass energy, which essentially combines all the energy in the system into one measurable quantity.

Imagine two cars smashing into each other, but instead of cars, they are highly energized particles. The center-of-mass energy tells us the energy of this 'smash' combining all factors.
Energy of Electrons
Electrons are tiny particles with a negative charge, and they play a crucial role in electricity and magnetism. In particle accelerators like the HERA Collider, electrons can be sped up to incredibly high energies.

In the given exercise, the energy of an electron is provided as 27.5 GeV.
To give you a sense of scale, 1 GeV (Giga-electron Volt) is a billion electron volts. This unit measures how much energy an electron has gained as it moves through an electric potential.

High-energy electrons are useful in many experiments and technologies, including those that help us understand fundamental particles and forces.
Energy of Protons
Protons are much more massive than electrons and carry a positive charge. They are found in the nuclei of atoms and play a central role in the structure of matter.

At particle colliders, protons can also be accelerated to extremely high energies. In the exercise, the proton's energy is given as 820 GeV, which is much greater than that of the electron.

This higher energy allows protons to smash into other particles and reveal new fundamental physics. Understanding the energy of protons in these collisions helps us probe the mysteries of the universe.
HERA Collider
The HERA Collider, or Hadron-Electron Ring Accelerator, is a famous facility that was used to collide electrons and protons.

Located in Germany, HERA allowed scientists to explore high-energy phenomena by accelerating particles to near light speed. In the exercise, the collision energies given are 27.5 GeV for electrons and 820 GeV for protons.

By understanding these high-energy collisions, scientists can investigate the fundamental particles and forces that make up our universe. The data obtained from HERA has contributed to many significant scientific discoveries.

Imagine it as a highly advanced laboratory where fundamental physics comes to life, helping us answer core questions about matter and energy.

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Most popular questions from this chapter

When expressed in natural units the lifetime of the \(\mathrm{W}\) boson is approximately \(\tau \approx 0.5 \mathrm{GeV}^{-1} .\) What is the corresponding value in S.I. units?

Find the maximum opening angle between the photons produced in the decay \(\pi^{0} \rightarrow \gamma \gamma\) if the energy of the neutral pion is \(10 \mathrm{GeV}\), given that \(m_{\pi^{a}}=135 \mathrm{MeV}\).

In a collider experiment, \(\Lambda\) baryons can be identified from the decay \(\Lambda \rightarrow \pi^{-} p\), which gives rise to a displaced vertex in a tracking detector. In a particular decay, the momenta of the \(\pi^{+}\)and \(p\) are measured to be \(0.75 \mathrm{GeV}\) and \(4.25 \mathrm{GeV}\) respectively, and the opening angle between the tracks is \(9^{\circ}\). The masses of the pion and proton are \(139.6 \mathrm{MeV}\) and \(938.3 \mathrm{MeV}\). (a) Calculate the mass of the \(\Lambda\) baryon. (b) On average, \(\Lambda\) baryons of this energy are observed to decay at a distance of \(0.35 \mathrm{~m}\) from the point of production. Calculate the lifetime of the \(\Lambda\).

Tau-leptons are produced in the process \(\mathrm{e}^{+} \mathrm{e}^{-} \rightarrow \tau^{+} \tau^{-}\)at a centre-of-mass energy of \(91.2 \mathrm{GeV}\). The angular distribution of the \(\pi^{-}\)from the decay \(\tau^{-} \rightarrow \pi^{-} v_{\tau}\) is $$ \frac{\mathrm{d} N}{\mathrm{~d}\left(\cos \theta^{*}\right)} \propto 1+\cos \theta^{*} $$ where \(\theta^{*}\) is the polar angle of the \(\pi^{-}\)in the tau-lepton rest frame, relative to the direction defined by the \(\tau(\) tau \()\) spin. Determine the laboratory frame energy distribution of the \(\pi^{-}\)for the cases where the tau-lepton spin is (i) aligned with or (ii) opposite to its direction of flight.

Show that the process \(\gamma \rightarrow \mathrm{e}^{+} \mathrm{e}^{-}\)can not occur in the vacuum.

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