Chapter 2: Problem 3
Show that the process \(\gamma \rightarrow \mathrm{e}^{+} \mathrm{e}^{-}\)can not occur in the vacuum.
Short Answer
Expert verified
The process \(\gamma \rightarrow \mathrm{e}^{+} \mathrm{e}^{-} \) cannot occur in vacuum due to violation of conservation laws of momentum and energy.
Step by step solution
01
Understand the problem
To show that the process \(\gamma \rightarrow \mathrm{e}^{+} \mathrm{e}^{-}\) cannot occur in the vacuum, analyze the conservation laws of energy and momentum.
02
Conservation of energy
In this process, a photon (\(\gamma\)) would convert into an electron (\(\mathrm{e}^{-}\)) and a positron (\(\mathrm{e}^{+}\)). For this to happen, the energy of the photon must equal the combined energy of the electron and positron. Mathematically, if the total energy of the photon is \(E_\gamma\), then \[ E_\gamma = E_{e^{-}} + E_{e^{+}} \]
03
Conservation of momentum
According to the conservation of momentum, the momentum of the photon must also equal the combined momentum of the electron and positron. Denote the photon's momentum as \(\mathbf{p_\gamma}\), the electron's as \(\mathbf{p_{e^{-}}}\), and the positron's as \(\mathbf{p_{e^{+}}}\). Thus, \[ \mathbf{p_\gamma} = \mathbf{p_{e^{-}}} + \mathbf{p_{e^{+}}} \]
04
Consider momentum in the frame of reference
In the vacuum, a photon is a massless particle moving with momentum \( \mathbf{p_\gamma} \). Meanwhile, an electron and positron each have non-zero rest mass \( m_{e} \). If we attempt to conserve both energy and momentum, we analyze in the reference frame where the initial photon's momentum is p.
05
Relate energy and momentum for the particles
For a photon, \(E_\gamma = p_\gamma c\), where \(c\) is the speed of light. For an electron and positron, their energies are given by \[ E_{e^{-}} = \sqrt{p_{e^{-}}^2c^2 + m_{e}^2c^4} \] and \[ E_{e^{+}} = \sqrt{p_{e^{+}}^2c^2 + m_{e}^2c^4}\] If their momenta are equal and opposite, i.e., \( \mathbf{p_{e^{-}}} = -\mathbf{p_{e^{+}}} \), then the total momentum of the system still equals \( \mathbf{p_\gamma} \).
06
Analyze the contradiction
Using the equations from the previous steps, determine whether simultaneous conservation of both energy and momentum can hold. Since both particles have rest mass, the minimum combined energy must be greater than zero. However, a photon with the same momentum in vacuum would have zero rest mass, leading to a contradiction that violates the conservation principles.
07
Conclude
Therefore, the process \( \gamma \rightarrow \mathrm{e}^{+} \mathrm{e}^{-} \) cannot occur in vacuum because it would violate the conservation of both energy and momentum.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Energy Conservation
In particle physics, energy conservation is a crucial principle. During any interaction or transformation, the total energy before the event must equal the total energy after the event.
For the process \( \gamma \rightarrow \mathrm{e}^+ \mathrm{e}^- \), a photon is expected to convert into an electron and a positron.
In this scenario, the photon's energy should equal the combined energy of the electron and the positron.
This can be represented mathematically as:
\[ E_\gamma = E_{e^-} + E_{e^+} \]
This equation ensures that the total energy remains conserved during the conversion.
However, there are other factors we need to consider, such as the nature of photons and other conservation laws.
For the process \( \gamma \rightarrow \mathrm{e}^+ \mathrm{e}^- \), a photon is expected to convert into an electron and a positron.
In this scenario, the photon's energy should equal the combined energy of the electron and the positron.
This can be represented mathematically as:
\[ E_\gamma = E_{e^-} + E_{e^+} \]
This equation ensures that the total energy remains conserved during the conversion.
However, there are other factors we need to consider, such as the nature of photons and other conservation laws.
Momentum Conservation
Alongside energy, momentum must also be conserved in particle interactions. Conservation of momentum states that the total momentum before an event must equal the total momentum afterward.
For the process \( \gamma \rightarrow \mathrm{e}^+ \mathrm{e}^- \), the initial momentum of the photon should equal the combined momentum of the electron and positron.
This relationship can be expressed as:
\[ \mathbf{p_\gamma} = \mathbf{p_{e^-}} + \mathbf{p_{e^+}} \]
Photons are unique because they are massless particles, so they travel at the speed of light with a momentum dependent on their energy.
Electrons and positrons, on the other hand, have rest mass. Thus, equating their momentum with the photon’s momentum can lead to complications, especially in a vacuum.
For the process \( \gamma \rightarrow \mathrm{e}^+ \mathrm{e}^- \), the initial momentum of the photon should equal the combined momentum of the electron and positron.
This relationship can be expressed as:
\[ \mathbf{p_\gamma} = \mathbf{p_{e^-}} + \mathbf{p_{e^+}} \]
Photons are unique because they are massless particles, so they travel at the speed of light with a momentum dependent on their energy.
Electrons and positrons, on the other hand, have rest mass. Thus, equating their momentum with the photon’s momentum can lead to complications, especially in a vacuum.
Pair Production
Pair production is a process where a photon turns into a particle-antiparticle pair, such as an electron and a positron. However, certain conditions must be met for this to occur.
The photon's energy needs to be high enough to create the mass of the electron-positron pair. This energy threshold is given by:
\[ E_\gamma \ge 2m_e c^2 \]
where \( m_e \) is the rest mass of the electron and \( c \) is the speed of light.
Additionally, for momentum conservation, an additional particle or field is usually required to balance the momentum, such as a nearby nucleus in a material.
In a vacuum, without this extra particle or field, achieving balanced momentum and energy simultaneously can be impossible.
The photon's energy needs to be high enough to create the mass of the electron-positron pair. This energy threshold is given by:
\[ E_\gamma \ge 2m_e c^2 \]
where \( m_e \) is the rest mass of the electron and \( c \) is the speed of light.
Additionally, for momentum conservation, an additional particle or field is usually required to balance the momentum, such as a nearby nucleus in a material.
In a vacuum, without this extra particle or field, achieving balanced momentum and energy simultaneously can be impossible.
Photon Interactions
Photons are elementary particles of light with zero rest mass and always travel at the speed of light in a vacuum.
They interact with matter in various ways, including absorption, reflection, and pair production.
However, in vacuum conditions, their interactions are constrained by the fundamental conservation laws of energy and momentum.
As highlighted earlier, for a photon to convert into an electron and positron, it needs to satisfy energy and momentum conservation.
In practical circumstances, this often involves intermediary particles, which are absent in a vacuum, rendering the conversion process impossible without them.
They interact with matter in various ways, including absorption, reflection, and pair production.
However, in vacuum conditions, their interactions are constrained by the fundamental conservation laws of energy and momentum.
As highlighted earlier, for a photon to convert into an electron and positron, it needs to satisfy energy and momentum conservation.
In practical circumstances, this often involves intermediary particles, which are absent in a vacuum, rendering the conversion process impossible without them.
Vacuum Conditions
A vacuum is a space devoid of matter, meaning there are no particles, atoms, or nuclei present. In such an environment, certain processes, like the one considered here \( \gamma \rightarrow \mathrm{e}^+ \mathrm{e}^- \), become particularly challenging.
This is because there's no additional mass or charge to help balance out the conservation laws of energy and momentum.
For pair production to proceed in a vacuum, both the electron and positron's rest mass must come solely from the photon's energy, which complicates satisfying both conservation laws simultaneously.
Therefore, understanding the constraints of a vacuum is essential when studying photon interactions and particle transformations.
This is because there's no additional mass or charge to help balance out the conservation laws of energy and momentum.
For pair production to proceed in a vacuum, both the electron and positron's rest mass must come solely from the photon's energy, which complicates satisfying both conservation laws simultaneously.
Therefore, understanding the constraints of a vacuum is essential when studying photon interactions and particle transformations.