Chapter 6: Problem 2
Show that the chiral projection operators $$ P_{\hat{A}}=\frac{1}{2}\left(1+\gamma^{5}\right) \quad \text { and } \quad P_{L}=\frac{1}{2}\left(1-\gamma^{5}\right), $$ satisfy $$ P_{\hat{A}}+P_{L}=1, \quad P_{\hat{h}} P_{R}=P_{\hat{A}}, \quad P_{L} P_{L}=P_{L} \quad \text { and } \quad P_{L} P_{R}=0 . $$
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