Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 10: Q16CQ (page 467)

Why does the small current flowing through a reverse biased diode depends much more strongly on temperature than on the applied (reverse) voltage?

Short Answer

Expert verified

The number of minority carriers depends less on the reverse voltage.

Step by step solution

01

Step-1: A concept:

It can be seen that in a reverse-biased diode, some current flows through the depletion region. This current is called leakage current.

02

Dependence of Minority Carriers on Temperature:

The minority carriers cause the small current to flow through a reverse-biased diode. The number of minority carriers depends on the temperature because at a higher temperature more minority carriers are available. The number of minority carriers depends less on the reverse voltage.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Based only on the desire to limit minority carriers, why would silicon be preferable to germanium as a fabric for doped semiconductors?

Question: - For a small temperature change. a material's resistivity (reciprocal of conductivity) will change linearly according to

p(dT)=ρ0+dρ=ρ0(1+αdT)

The fractional change in resistivity, αalso known as the temperature coefficient, is thus

α=1ρ0dρdT

Estimate forα silicon at room temperature. Assume a band gap of 1.1 e v .

The effective force constant of the molecular “spring” in HCL is 480 N/m, and the bond length is 0.13 nm.

(a) Determine the energies of the two lowest-energy vibrational states.

(b) For these energies, determine the amplitude of vibration if the atoms could be treated as oscillating classical particles.

(c) For these energies, by what percentages does the atomic separation fluctuate?

(d) Calculate the classical vibrational frequencyωvh=k/μand rotational frequency for the rotational frequencyωrot=L/I, assume that L is the its lowest non zero value, 1(1+1)hand that the moment of inertia Iis μa2.

(e) Is is valid to treat the atomic separation as fixed for rotational motion while changing for vibrational?

In a concise yet fairly comprehensive way. explain why doped semiconductors are so pervasive in modern technology.

Question: The interatomic potential energy in a diatomic molecule (Figure 10.16) has many features: a minimum energy, an equilibrium separation a curvature and so on. (a) Upon what features do rotational energy levels depend? (b) Upon what features do the vibration levels depend?
See all solutions

Recommended explanations on Physics Textbooks

Thermodynamics

Read Explanation

Atoms and Radioactivity

Read Explanation

Fields in Physics

Read Explanation

Work Energy and Power

Read Explanation

Force

Read Explanation

Dynamics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free