By the “vector” technique of example 10.1 , show that the angles between all lobes of the hybridsp3states are 109.5°..

Short Answer

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The Angle between all lobes of hybrid sp3states are109.5°

Step by step solution

01

Finding Four States that participate in hybrid.

ψ1=ψ2s-ψ2pzψ2=ψ2s+13ψ2pz-83ψ2pxψ3=ψ2s+13ψ2pz-23ψ2px-63ψ2pxψ4=ψ3=ψ2s+13ψ2pz-23ψ2px-63ψ2px

Now We will Use Dot product to Find The Angle.

A.B=AB Cosθ (Here A and B are vectors).

02

To Calculate the Dot Product.

Ignoring the 2s state contribution, to calculate the length of each state.

ψ1=-12=1ψ12=(13)+(83)2=1ψ3or4l2=(13)2+(23)2+(63)2=1ForDotProductsCalculation..ψ1.ψ2=0,0,1.(-83,0,13)=-13ψ2.ψ3or4=0,0,-1.(23±(63,13)=-13ψ2.ψ3or4=(23-(63,13).(23,(63,13)=29-69+19=-13InallcasestheDotProductis-13andthelengthisalways1.So,Cosθ=ABAB=-13θ=cos-1-13=109.5°..Hence,TheAnglebetweenalllobesofhybridsp3statesare109.5°

For Dot Products Calculation..

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