Chapter 10: Q49E (page 469)
In Figure 10.24, the n=1 band ends at , while in Figure 10.27 it ends at
Short Answer
It is proved that two ends are compatible.
Chapter 10: Q49E (page 469)
In Figure 10.24, the n=1 band ends at , while in Figure 10.27 it ends at
It is proved that two ends are compatible.
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Get started for freeThe diagram shows an idealization of the "floating magnet trick" of Figure 10.50. Before it is cooled, the superconducting disk on the bottom supports the small permanent magnet simply by contact. After cooling, the magnet floats. Make a sketch, showing what newmagnetic fields arse. Where are the currents that produce them?
The accompanying diagrams represent the three lowest energy wave functions for three "atoms." As in all truly molecular states we consider, these states are shared among the atoms. At such large atomic separation, however, the energies are practically equal, so anelectron would be just as happy occupying any combination.
(a) Identify algebraic combinations of the states (for instance, 5+11/2+11/2 ) that would place the electron in each of the three atoms.
(b) Were the atoms closer together, the energies of states 1.11, and III would spread out and an electron would occupy the lowest energy one. Rank them in order of increasing energy as the atoms draw closer together. Explain your reasoning.
In the boron atom, the single electron does not completely fill any spatial state, yet solid boron is not a conductor. What might explain this? (It may be helpful to consider again why beryllium is not an insulator.)
Vibration-rotation spectra are rich For the CO molecule (data are given in Exercise 42), roughly how many rotational levels would there be between the ground vibrational state and the first excited vibrational state?
Show that for a room-temperature semiconductor with a band gap of , a temperature rise of 4K would raise the conductivity by about 30%.
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