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Chapter 10: Q53E (page 470)

In diamond, carbon’s four full (bonding) s and p spatial states become a band and the four empty(anti bonding) ones becomes a higher energy band. Considering the trend in the band gaps of diamond, silicon, and germanium, explain why it might not be surprising that “covalent” tin behaves as a conducting metallic solid.

Short Answer

Expert verified

The number of electrons are large in the conduction band and it makes the time behaves like metallic solid.

Step by step solution

01

Determine the formulas

Consider the formula for the energy of the electron as:

E=hcλ

Here,λ is the wavelength, h is the plank’s constant, and c is the speed of light.

02

Determine the answer for the question:

Consider the energy gap of the diamond is 5.4 eV and the energy gap of the silicon is 1.1 eV and 0.7 eV in the germanium. In the same way the energy gap of the covalent tin is small and same is at the room temperature. Thus, the number of electrons are large in the conduction band and it makes the time behaves like metallic solid.

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Most popular questions from this chapter

Two dimensional lattices with three or four sided symmetries are possible but there is none with a five sided symmetry. To see why consider the following equilateral triangle or squares with no excess. Prove that this is not the case for equilateral pentagons.

The diagram shows a bridge rectifier circuit. A sinusoidal input voltage is fed into four identical diodes. each represented by the standard diode circuit symbol. The symbol indicates the direction of conventional current flow through the diode. The plots show input and output voltages versus time. Note that the output voltage is strictly in one direction. Explain

(a) how this circuit produces the unidirectional output voltage it does, and

(b) what features in the output plot indicate that the band gap of the diodes is about half an electronvolt, (It might seem that about one volt is correct, but consider how many diodes are on and in series at any given instant. In fact, although not the usual habit, it might be more accurate to plot the output voltage shifted upward relative to the input.)

Question: The diagram shows the energy bands of a tunnel diode as the potential difference is increased. In this device high impurity atom density causes the occupied donor and unoccupied acceptor levels to spread into impurity bands which overlap respectively the n-type conduction- and the p-type valence bands. In all unbiased diodes, the depletion zone between the n-type and p-type bands constitutes a potential barrier (see Section 6.2) but in the tunnel diode it is so thin that significant tunnelling occurs. The current versus voltage plot shows that unlike a normal diode significant current begins to flow as soon as there is an applied voltage—before the bias voltage is Egap /e. It then decreases (so called negative resistance) before again increasing in the normal way. Explain this behavior.

By the “vector” technique of example 10.1 , show that the angles between all lobes of the hybridsp3states are 109.5°..

What is Cooper pair, and what role does it play in superconductivity?
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