Chapter 10: Q74E (page 470)
Question: The critical temperature lead is 7.2 K. What is the binding energy of its Cooper pairs at zero temperature?
Short Answer
Answer
The binding energy of the Cooper pairs is 217meV.
Chapter 10: Q74E (page 470)
Question: The critical temperature lead is 7.2 K. What is the binding energy of its Cooper pairs at zero temperature?
Answer
The binding energy of the Cooper pairs is 217meV.
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Get started for freeBy the “vector” technique of example 10.1 , show that the angles between all lobes of the hybridstates are .
It takes less energy to dissociate a diatomic fluorine molecule than a diatomic oxygen molecule (in fact, less than one-third as much). Why is it easier to dissociate fluorine?
What factors decrease the conductivity of a conductor as temperature increases? Are these factors also present in a Semiconductor, and if so, how can its conductivity vary with temperature in the opposite sense?
Sketch an energy-versus-position diagram. Complementary to Figure 10.4, showing valence hole motion a conduction electron participation in an operating pnp transistor.
In section 10.2 , we discussed two-lobed and states and 4 lobed hybrid states. Another kind of hybrid state that sticks out in just one direction is the sp , formed from a single p state and an s state. Consider an arbitrary combination of the 2s state with the state. Let us represent this by(The trig factors ensure normalization in carrying out the integral , cross terms integrate to 0.leaving Which is 1.)
(a) Calculate the probability that an electron in such a state would be in the +z-hemisphere.(Note: Here, the cross terms so not integrate to 0 )
(b) What value of𝛕leads to the maximum probability, and what is the corresponding ratio of and ?
(C) Using a computer , make a density (Shading) plot of the probability density-density versus r and𝛉- for the𝛕-value found in part (b).
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