A tiny1μg particle is in a 1 cm wide enclosure and take a yearto bounce from one end to the other and back(a) Haw many nodes are there in the enclosure (b) How would your answer change if the particle were more massive or moving faster.

Short Answer

Expert verified

a.The nodes in the enclosure are2×1013 nodes .

b. When the particle is more massive or moving faster the momentum of the particle is increased resulting in shorter wavelength and the nodes will also increase

Step by step solution

01

Identification of given data 

The given data can be listed below,

  • The mass of the particle is,m=1 μg
  • The size of the enclosure is, L=1 cm
  • The taken to complete bounce back is,T=2 year(3.156×107 s1 year)
02

Concept/Significance of bound state

When the system is bounded in the conventional sense, a stationary state is said to be a bound state. In classical mechanics, a system with some finite energy cannot exist in a region of infinite potential energy in an infinite potential well.

It should be noted that the energy quantization only takes place when the system is bounded.

03

(a) Determination of the nodes are there in the enclosure 

The energy of the bound state is given by,

E=nh28mL2 …(i)

Here, nis the number nodes or state, h is the plank’s constant whose value is ν6.63×1034 Js, m is the mass of the particle and L is the length of enclosure.

According to Einstein, the photon energy of the particle is given by,

E=hν …(ii)

Here, νis the frequency of the particle.

Compare two equations the number of nodes is given by,

hν=nh28mL2n=8mL2hT

Substitute all the values in the above,

n=8(1 μg)(1 cm)2(6.63×1034 Js)(6.037×107 s)=1.99×1013 nodes2×1013 node

Thus, the nodes in the enclosure are 2×1013 nodes.

04

(b) Explanation of what will happen to nodes if the particle were more massive or moving faster.

The momentum would be greater if the particle moved more quickly or had more mass, which would suggest a shorter wavelength and, as a result, a greater number of nodes. It would never be anticipated to act as a wave since it would be more massive or travelling faster, and more mass.

Thus, when the particle is more massive or moving faster the momentum of the particle is increased resulting in shorter wavelength and the nodes will also increase

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Most popular questions from this chapter

To describe the matter wave, does the function Asin(kx)cosωthave well-defined energy? Explain

Simple models are very useful. Consider the twin finite wells shown in the figure, at First with a tiny separation. Then with increasingly distant separations, In all case, the four lowest allowed wave functions are planned on axes proportional to their energies. We see that they pass through the classically forbidden region between the wells, and we also see a trend. When the wells are very close, the four functions and energies are what we might expect of a single finite well, but as they move apart, pairs of functions converge to intermediate energies.

(a) The energies of the second and fourth states decrease. Based on changing wavelength alone, argue that is reasonable.

(b) The energies of the first and third states increase. Why? (Hint: Study bow the behaviour required in the classically forbidden region affects these two relative to the others.)

(c) The distant wells case might represent two distant atoms. If each atom had one electron, what advantage is there in bringing the atoms closer to form a molecule? (Note: Two electrons can have the same wave function.)

Given that the particle’s total energy is0, show that the potential energy is role="math" localid="1657529957489" U(x)=h22mb4x2-3h22mb2.

To show that the potential energy of finite well is U=h2(n1)28mL2

Show thatΔp=0p^ψ(x)=p¯ψ(x) that is, verify that unless the wave function is an Eigen function of the momentum operator, there will be a nonzero uncertainty in the momentumstarts with showing that the quantity

allspaceψ(x)(p^p¯)2ψ(x)dx

Is (Δp)2. Then using the differential operator form ofp^and integration by parts, show that it is also,

allspace{(p^p¯)ψ(x)}{(p^p¯)ψ(x)}dx

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