Using equation (23), find the energy of a particle confined to a finite well whose walls are half the height of the ground-state infinite well energy, . (A calculator or computer able to solve equations numerically may be used, but this happens to be a case where an exact answer can be deduced without too much trouble.)

Short Answer

Expert verified

The energy of a particle confined to a finite well whose walls are half the height of the ground-state infinite well energy is π228mL2.

Step by step solution

01

Given data

There is a finite well whose walls are half the height of the ground-state infinite well energy, E1.

02

Ground state energy of infinite potential well and height of the finite potential well

The ground state energy of a particle of mass in an infinite well of width L is

E=π222mL2 .....(I)

Here is the reduced Planck's constant.

The height of the finite potential well is

U0=2k22msec2kL2n-1π<kL<nπn=1,3,5...2k22mcsc2kL2n-1π<kL<nπn=2,4,6... .....(II)

03

Determining the energy of the finite well

The height of the well is half the ground state energy of an infinite potential well. Thus for n = 1

U0=E12

Substitute from equations (I) and (II) to get

2k22msec2kL2=π224mL2k2sec2kL2=π22L2cos2kL2=2k2L2π2

This has a solution for

k=π2L

The corresponding energy is

E=2k22m=22m×π24L2=π228mL2

Thus the required energy is π228mL2.

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