For a total energy of 0, the potential energy is given in Exercise 96. (a) Given these, to what region of the x-axis would a classical particle be restricted? Is the quantum-mechanical particle similarly restricted? (b) Write an expression for the probability that the (quantum-mechanical) particle would be found in the classically forbidden region, leaving it in the form of an integral. (The integral cannot be evaluated in closed form.)

Short Answer

Expert verified

(a) Classically allowed region is -3b,3b.

(b) Forbidden region is 230bA2X2e-x2ib2dx.

Step by step solution

01

Relationship between the total energy and the potential energy

The half of the potential energy is known as the total energy.

02

Step 2(a): The classically allowed region

As we know the potential energy is

Ux=h22mb4x2-3h22mb2Ux=22mb4x2-3×22mb2=22m-3b2+1b4x2

The potential energy is smaller than 0 when the region is classically allowed.

-3b2+1b4x2=0x2=3b2x=-3b,3b

So, the classically allowed region is -3b,3b.

The wave function extends infinitely far in both directions, so the quantum entity is not restricted to this region.

03

The probability of the particle

The probability for the particle is

-3b3bΨxΨ0xdx=-3b3bA2x2e-x2ib2dx=203bA2x2e-x2ib2dx

Therefore, the probability that the particle would be found in the classical forbidden region is 203bA2x2e-x2ib2dx.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Outline a procedure for predicting how the quantum-mechanically allowed energies for a harmonic oscillator should depend on a quantum number. In essence, allowed kinetic energies are the particle-in-a box energies, except the length Lis replaced by the distance between classical tuning points. Expressed in terms of E. Apply this procedure to a potential energy of the form U(x) = - b/x where b is a constant. Assume that at the origin there is an infinitely high wall, making it one turning point, and determine the other numing point in terms of E. For the average potential energy, use its value at half way between the tuning points. Again in terms of E. Find and expression for the allowed energies in terms of m, b, and n. (Although three dimensional, the hydrogen atom potential energy is of this form. and the allowed energy levels depend on a quantum number exactly as this simple model predicts.)

A bound particle of massdescribed by the wave function

ψ(x)=Axe-x2/2b2

What is the most probable location at which to find the particle?

To determine the classical expectation value of the position of a particle in a box is L2 , the expectation value of the square of the position of a particle in a box isrole="math" localid="1658324625272" L23 , and the uncertainty in the position of a particle in a box isL12 .

Consider a particle of mass mand energy E in a region where the potential energy is constant U0. Greater than E and the region extends tox=+

(a) Guess a physically acceptable solution of the Schrodinger equation in this region and demonstrate that it is solution,

(b) The region noted in part extends from x = + 1 nm to +. To the left of x = 1nm. The particle’s wave function is Dcos (109m-1 x). Is also greater than Ehere?

(c) The particle’s mass m is 10-3 kg. By how much (in eV) doesthe potential energy prevailing from x=1 nm to U0. Exceed the particle’s energy?

In several bound systems, the quantum-mechanically allowed energies depend on a single quantum number we found in section 5.5 that the energy levels in an infinite well are given by, En=a1n2wheren=1,2,3.....andis a constant. (Actually, we known whata1is but it would only distract us here.) section 5.7 showed that for a harmonic oscillator, they areEn=a2(n12), wheren=1,2,3.....(using ann12with n strictly positive is equivalent towith n non negative.) finally, for a hydrogen atom, a bound system that we study in chapter 7,En=a3n2, wheren=1,2,3.....consider particles making downwards transition between the quantized energy levels, each transition producing a photon, for each of these three systems, is there a minimum photon wavelength? A maximum ? it might be helpful to make sketches of the relative heights of the energy levels in each case.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free