Table 12.1 gives the width of the K0 meson

(a) Approximately what is the its lifetime?.

(b) This meson’s actual radius is on the order 1 fm. Would its constituents have the time to bounce around inside a great deal?

Short Answer

Expert verified

(a) The lifetime of this particle is about 1×10-23s.

(b)The constituents do not have enough time to bounce around inside.

Step by step solution

01

Given data

Width of K*0 mesons =51MeV

02

Concept of lifetime

The lifetime of this particle by the formula,

τ=width

The distance dcan be expressed as:

d=τc

Here c is the speed of light.

03

 Step 3:Determine the lifetime of this particle

(a)

The width of K*0 is given to be 51MeV, so the lifetime can be calculated as shown below.

τ=width=1.055×10-34J·s51MeV1eV1.6×10-19J=1×10-23s

Therefore, the lifetime of this particle is about 1×10-23s.

04

Determine whether the constituents have the time to bounce around inside or not

(b)

Substitute 1×10-23s for τ and 3×108m/sfor c as:

d=1×10-23s3×108m/s=3×10-15m=3×10-15m1fm10-15m=3fm

The calculated value 3×10-15m is less than that of the radius ( 1fm ) of mesons.

Therefore, the constituents do not have enough time to bounce around inside.

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