Chapter 11: Q2CQ (page 517)
Question:How is it that a high binding energy is a low energy?
Short Answer
Answer
The nucleus is harder to be broken apart, that is to say, the nucleus is more stable and at a lower energy state.
Chapter 11: Q2CQ (page 517)
Question:How is it that a high binding energy is a low energy?
Answer
The nucleus is harder to be broken apart, that is to say, the nucleus is more stable and at a lower energy state.
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Get started for freeA fossil specimen has decay rate of
(a) How many carbon-14 nuclei are present?
(b) If the specimen is 20,000 years old, how many carbon-14 nuclei were present when the animal died?
(c) How much kinetic energy (in MeV) is released in each decay and what is the total amount released in all decay since the animal died?
You occupy a one-dimensional world in which beads of mass when isolated-attract each other if and only if in contact. Were the beads to interact solely by this attraction, it would take energy to break the contact. Consequently. We could extract this much energy by sticking two together. However, they also share a repulsive force, no matter what their separation. For which the potential energy is . Whererole="math" localid="1660033271423" is a bead's radius and is centre to centre separation. The closer the beads. The higher is this energy.
(a) For one stationary bead, by how much does the energy differ from?
(b) For two stationary beads in contact, by how much does the energy differ from ?
(c) For three beads in contact (in a line, of course, since this world is one-dimensional). by how much does the energy differ from ?
(d) For four beads in contact, by how much does the energy differ from ?
(e) If you had 12 isolated beads and wished to extract the most energy by sticking them together (in linear groupings), into sets of what number would you group them?
(f) Sets of what number would be suitable fuel for the release of fusion energy? Or fission energy?
The total kinetic energy carried by the products of the spontaneous fission of plutonium – 240 is typically about 180 MeV. Use this to argue there that reduction in Coulomb repulsion is the major impulse behind the process. Assume for simplicity that the two fragment nuclei are of equal Z.
Question: Explain 10 your perplexed friend how you can bring, together twelve objects of mass 1.01 and end up with one object of mass 12.00
By classical, hard sphere assumption, what smallest value of would make one nucleon surrounded. Relate your answer with figure 11.14.
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