The semi empirical binding energy formula predicts the binding energies of neon-20, iron- 56, and uranium-238 within about 1\%. Make a 3×9 table whose rows are the three isotopes, whose first four columns are numerical values of the four tennis in the formula, whose next four columns are each of these terms divided byA, and whose final column is the sum of the preceding four. Discuss in some detail what the table reveals.

Short Answer

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The resultant answer is the table expressed.

Step by step solution

01

Given data

Mass number of neon-20ANe=20

Mass number of iron-56AFe=56

Mass number of uranium-238AU=238

Atomic number of neonZNe=10

Atomic number of ironZFe=26

Atomic number of uranium ZII=92

02

Formula of Semi empirical binding Energy

Semi empirical binding Energy is given by the expression,

BE=c1A-c2A2/3-c3Z(Z-1)A1/3-c4(N-Z)2A

03

Calculate the semi empirical binding energy

The semi-empirical binding energy formula isBE=c1A-c2A2/3-c3Z(Z-1)A1/3-c4(N-Z)2A.

For neon20,A=20,Z=10:

N=A-ZN=20-10N=10

For iron-56,A=56,Z=26:

N=A-ZN=56-26N=30

For uranium-2358,A=238,Z=92:

N=A-ZN=238-92N=146

The volume per nucleon contribution is the same: the surface term effect is bigger when the smaller the nucleus is because surface is a bigger proportion of the nucleus if the nucleus is smaller.

The third term effect is bigger for bigger nuclei, because the bigger nucleus has more protons.

The last term effect is bigger for bigger nuclei, because the asymmetry is more severe in bigger nuclei,

So, as number of nucleons increase, the surface effect gets smaller, but the Coulomb term and the asymmetry term effect gets bigger.

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