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Chapter 11: Q44E (page 519)

Find Q for the decay of beryllium-10

Short Answer

Expert verified

The Q factor is 0.56 MeV.

Step by step solution

01

Given data

Given that,410Be→510B+−10e+v¯.

Atomic mass of 410Be,mBe=10.013534u.

Atomic mass of 510B,mB=10.012937u.

02

Definition of Kinetic Energy

The kinetic energy released is, Q=(mi−mf)c2.

Where, mi is the mass of parents’ nucleus, mfis the mass of the daughter nucleus, and c is the speed of light in vacuum.

03

Determine the Kinetic Energy released

Kinetic energy released, Q=(mi−mf)c2.

The conversion factor may be used to express, c2→MeV/u.

Q=(mBe−mB)931.5MeVuQ=(10.013534u−10.012937u)931.5MeVuQ=0.56MeV

The Q factor is 0.56 MeV.

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