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Chapter 2: Q20E (page 62)

Through a window in Carl's spaceship, passing al 0.5c, you watch Carl doing an important physics calculation. By your watch it takes him 1 min. How much time did Carl spend on his calculation?

Short Answer

Expert verified

The time spends by Carl in spaceship for calculation is0.87min.

Step by step solution

01

Identification of given information

The given data can be listed below as:

  • The speed of spaceship is, v=0.5c.
  • The time measured by watch is, .
02

Usage of time dilation concept

The problem is based on the concept of time dilation. The spaceship for this problem is moving at half the speed of light.

03

Determination of the formula of the time dilation for spaceship

The formula to calculate the time dilation for spaceship is:

t2=t11-v2c2

04

Determination of the time dilation for spaceship

Substitute all the values in the above equation.

1min=t11-(0.5c)2c2t1=0.87min

Therefore, the time spend by Carl in spaceship for calculation is0.87min.

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Most popular questions from this chapter

Anna and Bob are In identical spaceships, each 100 m long. The diagram shows Bob's, view as Anna's ship passes at 0.8c. Just as the backs of the ships pass one another, both clocks.there read O. At the instant shown, Bob Jr., on board Bob's ship, is aligned with the very front of Anna's ship. He peers through a window in Anna's ship and looks at the clock. (a) In relation to his own ship, where is Bob Jr? (b) What does the clock he sees read?

What is the momentum of a proton accelerated through 1gigavolts (GV)?

How much work must be done to accelerate an electron

(a) from 0.3cto 0.6cand

(b) from 0.6cto 0.9c?

Question: Here we verify the conditions under which in equation (2-33) will be negative. (a) Show that is equivalent to the following:

vc>u0c21+u02/c2

(b) By construction v, cannot exceed u0, for if it did, the information could not catch up with Amy at event 2. Use this to argue that if u0<c, then must be positive for whatever value is allowed to have(x-1)2⩾0. (c) Using the fact that , show that the right side of the expression in part (a) never exceeds . This confirms that when u0>cv need not exceed to produce a negativet'3 .

According Anna, on Earth, Bob is on a spaceship moving at 0.8c toward Earth, and Carl, a little farther out. is on a spaceship moving at 0.9c toward Earth. (a) According to Bob, how fast and in what direction is Carl moving relative to himself (Bob)? (b) According to Bob, how fast is Carl moving relative to Earth?
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