Demonstrate that equations (2 - 12) and (2 - 13) become the classical transformation equations (2 - 1) when v << c, except when applied to events very far away, in which case time is still not absolute.

Short Answer

Expert verified

At low speeds, the Lorentz transformation equations will change into the well-known classical Galilean transformation equations, with the exception that time will start to take up a component that relies on location, making it no longer be an absolute. The influence must be considered even though we won't recognise it until we are very far away from reality.

Step by step solution

01

Write the given data from the question.

Consider that equations (2 - 12) and (2 - 13) become the classical transformation equations (2 - 1) when v << c.

02

Determine the formula of Lorentz transformation equations at low speeds.

Write the formula of Lorentz transformation equations at low speeds.

x'=γv(x-vt) …… (1)

Here, γv is relativistic velocity transformation, t is time, v is speed, x is transformation position and c speed of light.

03

Determine the value of Lorentz transformation equations at low speeds.

The Galilean transformation, which is ultimately expressed in Newton's equations, should be the limit of the Lorentz transformation. Let's see what a Lorentz transformation will appear to be at different speeds.

Determine the Lorentz transformation equations at low speeds (v << c).

Substitute 11-v2c2for γvinto equation (1).

x'=11-v2c2x-vt

Since,

v<<c1-v2c21

Then will be:

x'=x-vt …… (2)

In essence, you will do the same for the remaining equations: put the factor of equal to one, and then rewrite the equations as follows:

t'=t-vxc2 …… (3)

Then, Galilean transformation equations are:

x=x'+vt' …… (4)

And time equations are:

t=t'+vx'c2 …… (5)

The Galilean transformation is perfectly represented by equations (3) and (5), but if you look at the time equations (Eqs 4 and 6), you'll see that it wasn't entirely recovered. We kind of adopted some of the concepts from special relativity, which holds that time is relative and dependent on one's position in space rather than being an absolute. At low velocities, this effect will, however, be insignificant and imperceptible due to the speed of light squared in the denominator of the second term. Large distances, or particularly big distances, require study of this issue since it becomes relevant in certain cases.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) Determine the Lorentz transformation matrix giving position and time in framefromS'those in framein the classical limitlocalid="1657533931071" v<<c. (b) Show that it yields equations (2-1).

Anna and Bob are In identical spaceships, each 100 m long. The diagram shows Bob's, view as Anna's ship passes at 0.8c. Just as the backs of the ships pass one another, both clocks.there read O. At the instant shown, Bob Jr., on board Bob's ship, is aligned with the very front of Anna's ship. He peers through a window in Anna's ship and looks at the clock. (a) In relation to his own ship, where is Bob Jr? (b) What does the clock he sees read?

Question: The weight of the Empire State Building is . Show that the complete conversion of of mass would provide sufficient energy to putli.is rather a large object in a low Earth orbit or LEO for short. (Orbit radius Earth's radius).

According to Bob, on Earth, it is 20ly to Planet Y. Anna has just passed Earth, moving at a constant speed υ in a spaceship, When Anna passes Planet Y. She is 20years older than when she passed Earth. Calculate ν.

A thin plate has a round hole whose diameter in its rest is D. The plate is parallel to the ground and moving upward, in the +y direction, relative to the ground. A thin round disk whose diameter in its rest frame is D direction is also parallel to the ground but moving in the +x relative to it. In the frame of the ground, the plate and disk are on course so that the centers of the bole and disk wiIl at some point coincide. The disk is contracted, but the hole in the plate is not, so the disk will pass through the hole. Now consider the frame of the disk. The disk is of diameter D, but the hole is contracted. Can the disk pass through the hole, and if so, how?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free