Consider Anna, Bob and Carl in the twin paradox.

(a) According to Anna, when Planet X passes her, clocks on Planet X and Earth tick simultaneously. What is the time interval between these two events in the Earth-Planet X frame?

(b) According to Carl, when Planet X passes, clocks on Planet X and Earth tick simultaneously. What is the time interval between these two events in the Earth-Planet X frame?

(c) What does the clock on Planet X read when Carl and Anna reach it? Show how your results from part (a) and (b) agree with Figure 2.20.

Short Answer

Expert verified

(a) When the two ticks are simultaneous in Anna's frame, the time interval in the Earth-Planet X frame is 32y.

(b) When the two ticks are simultaneous in Carl's frame, the time interval in the Earth-Planet X frame is -32y.

(c) When Carl and Anna reach Planet X, the clock reads 50y, which is in agreement with Figure 2.20.

Step by step solution

01

Given data

Speed of Anna and Carl with respect to Earth-Planet X frame is,

v=0.8c

The distance of planet X from Earth with respect to Anna and Carl is,

l'=24 ly

02

Lorentz transformation

The time interval of two events measured by a stationary observer is related tothe time interval measured by a moving observer at velocity and the space interval of the two events measured by the moving observer as,

t=t'+vc2x'1v2c2 .....(I)

Here c is the speed of light in vacuum.

03

Step 3:Determining time interval with respect to Earth-Planet X frame(a)

The time interval of the two ticks with respect to Anna and Carl is 0. The velocity of Anna with respect to Earth-Planet X frame is 0.8c.Thus from equation (I), the time interval according to the stationary frame is,

t=0+0.8cc224c y10.82=32 y

Thus, when the two ticks are simultaneous in Anna's frame, the time interval in the Earth-Planet X frame is 32y.

(b)

The velocity of Carl with respect to Earth-Planet X frame is 0.8c. Thus from equation (I), the time interval according to the stationary frame is,

t=0+0.8cc224c y10.82=32 y

Thus, when the two ticks are simultaneous in Carl's frame, the time interval in the Earth-Planet X frame is -32y.

04

Determining reading on the clock on Planet X

(c)

The clock on Planet X is in a stationary frame and runs at the same rate as that of Bob's clock. According to that clock, it took 50 y for Anna to reach Planet X.,So the clock reads 50 y. According to Anna, the Planet X clock is ahead of the Earth clock by 32 y. So, according to her, the Earth clock reads 18 y, which is her estimate of Bob's age. According to Bob, the Planet X clock is behind the Earth clock by 32 y. So, according to him, the Earth clock reads 82 y, which is his estimate of Bob's age.

Thus, when Carl and Anna reach Planet X, the clock reads 50y , which is in agreement with Figure 2.20.

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Most popular questions from this chapter

Exercise 117 Gives the speed u of an object accelerated under a constant force. Show that the distance it travels is given byx=mc2F1+Ftmc2-1.

A proton is accelerated from rest through a potential difference of 500MV.

(a) What is its speed?

(b) Classical mechanics indicates that quadrupling the potential difference would double the speed. Were a classical analysis valid, what speed would result from a 2000MVpotential difference?

(c) What speed actually results?

A 3.000uobject moving to the right through a laboratory at 0.6ccollides with a 4.000uobject moving to the left through the laboratory at 0.6c. Afterward, there are two objects, one of which is a 6.000umass at rest.

(a) What are the mass and speed of the other object?

(b) Determine the change in kinetic energy in this collision.

In Example 2.5, we noted that Anna could go wherever she wished in as little time as desired by going fast enough to length-contract the distance to an arbitrarily small value. This overlooks a physiological limitation. Accelerations greater than about 30g are fatal, and there are serious concerns about the effects of prolonged accelerations greater than 1g. Here we see how far a person could go under a constant acceleration of 1g, producing a comfortable artificial gravity.

(a) Though traveller Anna accelerates, Bob, being on near-inertial Earth, is a reliable observer and will see less time go by on Anna's clock (dt') than on his own (dt). Thus,, whereuis Anna's instantaneous speed relative to Bob. Using the result of Exercise 117(c), withgreplacingF/m, substitute for u, then integrate to show that

(b) How much time goes by for observers on Earth as they “see” Anna age 20 years?

(c) Using the result of Exercise 119, show that when Anna has aged a timet’, she is a distance from Earth (according to Earth observers) of

(d) If Anna accelerates away from Earth while aging 20 years and then slows to a stop while aging another 20. How far away from Earth will she end up and how much time will have passed on Earth?

Using equations (2-20), show that

y'u=(1-uxvc2)yv,yu

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