At t=0, a bright beacon at the origin flashes, sending light uniformly in all directions. Anna is moving at speed v in the +x direction relative to the beacon and passes through the origin at t=0. (a) Show that according to Anna, the only light with a positivex'-component is that which in the beacon’s reference frame is within an angle θ=cos-1(v/c)of the +x -axis. (b) What are the limits of θ as v approaches 0 and as it approaches c? (c) The phenomenon is called the head-light effect. Why?

Short Answer

Expert verified

(a) Use a frame moving with the same x-component of the velocity of a light beam.

(b)

The value of limit where v=0approaches at an angle of θ=90°.

The value of limit where v=capproaches at an angle of θ=0°.

(c) The phenomenon is known as the light beam maintaining constant speed across all frames of reference; it will continue to travel in front of Anna even if she moves at a speed of v=c.

Step by step solution

01

Write the given data from the question.

Consider at t=0 , a bright beacon at the origin flashes, sending light uniformly in all directions. Anna is moving at speed v in the +x direction relative to the beacon and passes through the origin at t=0.

02

Determine the formula of beacon’s reference frame is within an angle θ of the +x-axis.

Write the formula of beacon’s reference frame is within an angle θof the +x-axis.

u'x=ux-v1-uxVc2 …… (1)

Here, ux is certain velocity, v is moving speed and c is speed of light.

03

(a) Determine the value of beacon’s reference frame is within an angle θ of the +x-axis.

Length contraction happens in the same direction of motion as Anna travels in the x-direction with a velocity v, but the vertical component maintains the same value (I may refer here to problems38and 39of this chapter). The conclusion is that these items appear to have been at different angles. The following relation will be reached mathematically if we suppose that we are travelling with the same x-component of a light beam in frameS'.

Determine the beacon’s reference frame is within an angle θof the +x-axis.

Substitute 0 for ux'and ccosθ for v into equation (1).

0=ccosθ-v1-uxvc2ccosθ-v=0ccosθ=vθ=cos-1vc

Remember that the denominator of the velocity transformation relation is always positive (for speeds less than c) and thus for a given velocity ux=v, Anna will distinguish between positive and negative values of the velocity recorded in her reference frame.

04

(b) Determine the value of limit where different approaches at different angles.

To examine the limiting situations, let's now utilise the previous relation:

1. The angle θwill equal π2=90°if v=0, or when this frame is motionless with regard to the bright beacon. By extension, both frames will include just positive light that is released in the positive x -direction, say on her right.

2. The angle will be zero when v=c, which denotes that Anna will be travelling at the speed of light. In other words, the window where Anna perceives the light is becoming smaller until it finally reduces to a single line. According to Anna, the light beam will be regarded as positive if it is travelling along the positive x-axis. The remainder of the beams, however, will appear to include a negative element.

05

(c) Determine the phenomenon is called the head-light effect.

In every frame of reference, the overall velocity's magnitude remains constant atc. The relative velocity between the observer and the light beam will remain constant, even for an observer travelling at the speed of light. Since Anna and the light are synchronised att=t'=0, the light will continue to move ahead of her.

Therefore, the phenomenon is known as the light beam maintaining constant speed across all frames of reference; it will continue to travel in front of Anna even if she moves at a speed of v=c.

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