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Chapter 8: Q17CQ (page 338)

Question: What if electrons were spin32 instead of spin 12. What would be Z for the first noble gas?

Short Answer

Expert verified

Answer

The value of z = 4.

Step by step solution

01

Introduction

Assume electrons had spin s=32 there would be 2s+1=4 possible spin orientations along the given z-axis

02

Value of z.

It would have z=4.

The first noble gas would have 4 electrons in its 1s state, namely one for each of the possible spin orientations, to have a complete outer shell. It would therefore have z = 4 .

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Most popular questions from this chapter

The general rule for adding angular momenta is given in Exercise 66, when adding angular momenta withj1=2 and j2=32

(a) What are the possible values of the quantum numberjT and the total angular momentum jT.

(b) How many different states are possible and,

(c) What are the (jT,mjT)values for each of these states?

Identify the different total angular momentum states j,mj allowed a 3d electron in a hydrogen atom.

In its ground state, nitrogen's 2p electrons interact to produce jT=32. Given Hund's rule, how might the orbit at angular momenta of these three electrons combine?

Question: Solving (or attempting to solve!) a 4-electron problem is not twice as hard as solving a 2-electrons problem. Would you guess it to be more or less than twice as hard? Why?

What angles might the intrinsic angular momentum vector make with the z-axis for a deuteron? (See Table 8.1)
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