Question: Huge tables of characteristic X-rays start at lithium. Why not hydrogen or helium?

Short Answer

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Answer

X-rays do not start at hydrogen or helium because all of the electrons are n= 1 electrons.

Step by step solution

01

Definition of electron configuration

In atomic physicsandquantum chemistry, the electron configuration is the distribution ofelectronsof anatomormolecule(or other physical structure) inatomicormolecular orbitals.

02

Calculate electronic configuration for hydrogen and helium

Given that the atomic number of hydrogen is Z (H) =1

The atomic number of helium is Z (He) =2

The electron configuration for hydrogen is 1s1

The electron configuration for helium is 1s2

03

Determine the reason

As we see, all of the electrons of hydrogen/helium are on the n = 1 level and this is the only level (shell) present. In order for the X-rays to be created, there must be a hole where an upper electron will fall which is not the case for hydrogen and helium.

Therefore X-rays do not start at hydrogen or helium because all of the electrons are n= 1 electrons.

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Most popular questions from this chapter

Question: In classical electromagnetism, the simplest magnetic dipole is a circular current loop, which behaves in a magnetic field just as an electric dipole does in an electric field. Both experience torques and thus have orientation energies -p.Eand-μ·B.(a) The designation "orientation energy" can be misleading. Of the four cases shown in Figure 8.4 in which would work have to be done to move the dipole horizontally without reorienting it? Briefly explain. (b) In the magnetic case, using B and u for the magnitudes of the field and the dipole moment, respectively, how much work would be required to move the dipole a distance dx to the left? (c) Having shown that a rate of change of the "orientation energy'' can give a force, now consider equation (8-4). Assuming that B and are general, write-μ·B.in component form. Then, noting thatis not a function of position, take the negative gradient. (d) Now referring to the specific magnetic field pictured in Figure 8.3 which term of your part (c) result can be discarded immediately? (e) Assuming thatandvary periodically at a high rate due to precession about the z-axis what else may be discarded as averaging to 0? (f) Finally, argue that what you have left reduces to equation (8-5).

The radius of cesium is roughly0.26nm.

(a) From this estimate the effective charge its valence electron orbits

(b) Given the nature of the electron's orbit. is this effective nuclearcharge reasonable?

(c) Compare this effective Zwith that obtained for sodium in Example 8.3. Are the values at odds with the evidence given in Figure8.16that it takes less energy to remove an electron from cesium than from sodium? Explain.

What is the angle between Land Sin a (a) 2p3/2and(b) 2p1/2 state of hydrogen?

Two particles in a box occupy the n=1andn'=2individual-particle states. Given that the normalization constant is the same as in Example8.2(see Exercise 36), calculate for both the symmetric and antisymmetric states the probability that both particles would be found in the left side of the box (i.e., between 0 and13L)?

In its ground state, nitrogen's 2p electrons interact to produce jT=32. Given Hund's rule, how might the orbit at angular momenta of these three electrons combine?

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