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Chapter 8: Q50E (page 342)

Determine the expected valence of the element with atomic number 117.

Short Answer

Expert verified

The expected valence of the element with atomic number117is +7 or -1.

Step by step solution

01

Given data

The given data is an element with atomic number 117 .

02

Concept of Electronic configuration 

Electronic configuration, also called electronic structure, the arrangement of electrons in energy levels around an atomic nucleus.

03

Determine the element 

The unknown element 117 falls in the column of fluorine, chlorine, etc., in which the elements have a valence of -1.

Accordingly, we expect, by the periodicity of the periodic table that the valence of element 117 to is -1 .

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Most popular questions from this chapter

Consider Z=19potassium. As a rough approximation assume that each of itsn=1electron s orbits 19 pro. tons and half an electron-that is, on average, half its fellown=1electron. Assume that each of itsn=2electrons orbits 19 protons, two Is electrons. and half of the seven othern=2electrons. Continue the process, assuming that electrons at eachorbit a correspondingly reduced positive charge. (At each, an electron also orbits some of the electron clouds of higher. but we ignore this in our rough approximation.)

(a) Calculate in terms ofa0the orbit radii of hydrogenlike atoms of these effective Z,

(b) The radius of potassium is often quoted at around0.22nm. In view of this, are yourn=1throughn=3radii reasonable?

(c) About how many more protons would have to be "unscreened" to then=4electron to agree with the quoted radius of potassium? Considering the shape of its orbit, should potassium'sn=4electron orbit entirely outside all the lower-electrons?

Question: Solving (or attempting to solve!) a 4-electron problem is not twice as hard as solving a 2-electrons problem. Would you guess it to be more or less than twice as hard? Why?

The Slater determinant is introduced in Exercise 42. Show that if states nand n'of the infinite well are occupied and both spins are up, the Slater determinant yields the antisymmetric multiparticle state:ψn(x1)↑ψn'(x2)↑−ψn'(x1)↑ψn(x2)↑

Imagine two indistinguishable particles that share an attraction. All other things being equal, would you expect their multiparticle spatial state to be symmetric, ant symmetric, or neither? Explain.

Question: Early on, the lanthanides were found to be quite uncooperative when attempts were made to chemically separate them from one another. One reason can be seen in Figure 8.16. Explain.
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