Determine the rank according to increasing wavelength ofkα,kβ andLα.

Short Answer

Expert verified

The ranking of the spectral lines from lowest to highest is Kβ,Kα and Lα.

Step by step solution

01

 Step 1: Given data

The given data spectral lines Kβ,Kα andLα .

02

 Step 2: Concept of Energy

The energy E of the emitted ray is inversely proportional to the wavelength λ:

E~1λ

03

Determine the electronic configuration

The Kα line corresponds to the transition from n=2 to n=1.

The Kβ line corresponds to the transition from n=3 to n=1.

The Lα line corresponds to the transition from n=3 to n=2.

The energy E of the emitted ray is inversely proportional to the wavelengthλ , E~1λ.

We know that with increasing n , the energy difference ΔE becomes smaller.

Thus, the highest energy of the photon corresponds to the Kβ line.

The next one is the Kα line and the last one is the Lα line. In terms of the wavelength, we can rank the wavelengths from smallest to greatest as, λKβ<λKα<λLα.

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