Using the relationship between temperature and MandN given in (9-16) and that betweenE andn in (9-6), obtain equation (9-17) from (9- 12). The first sum given In Exercise 30 will be useful.

Short Answer

Expert verified

The expression for P(En) is NN+Me-ln(1+NM)

Step by step solution

01

Boltzmann Distribution.

The Boltzmann distribution for a system of particles in terms of n, M, and N is given by:

P(En)=NM+Ne-n  ln(1+NM)

Boltzmann Probability in terms ofEnandkBT:

P(En)=e-EnkBTn=0e-EnkBT

02

System of  N Harmonic Oscillators.

En=nhω0P(En)=e-nhω0kBTn=0e-nhω0kBT=e-nhω0kBTn=0[e-nhω0kBT]n

03

Properties.

n=0xn=11-x

Denominator of P:

P(En)=e-nhω0kBT11-e-nhω0kBT=(1-e-nhω0kBT)e-nhω0kBTkBT=hω0ln(1+NM)hω0kBT=ln(1+NM)

On further calculation,

P(En)=(1-e-ln(1+NM))e-ln(1+NM)=1-1e-ln(1+NM)e-ln(1+NM)=1-11+NMe-ln(1+NM)=1+NM-11+NMe-ln(1+NM)=NM(M+N)Me-ln(1+NM)=NN+Me-ln(1+NM)

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Most popular questions from this chapter

Show that equation (9- 16) follows from (9-15) and (9- 10).

The electromagnetic intensity thermally radiated by a body of temperature Tis given by I=σT4whereσ=5.67×108W/m2K4

This is known as the Stefan-Boltzmann law. Show that this law follows from equation (9-46). (Note: Intensity, or power per unit area, is the product of the energy per unit volume and distance per unit time. But because intensity is a flow in a given direction away from the blackbody, the correct speed is not c. For radiation moving uniformly in all directions, the average component of velocity in a given direction is14c .)

Calculate the Fermi energy for copper, which has a density of8.9×103kg/m3and one conduction electron per atom. Is room temperature "cold"?

According to Wien's law, the wavelengthλmaxat which the thermal emission of electromagnetic energy from a body of temperatureTis maximum obeysλmaxT=2.898×103mK.Show that this law follows from equation (9-47). To do this. Usef=c/λto expressin terms ofλrather than f, then obtain an expression that, when solved, would yield the wavelength at which this function is maximum. The transcendental equation cannot be solved exactly, so it is enough to show thatλ=(2.898×103mK)/T solves it to a reasonable degree of precision.

Somehow you have a two-dimensional solid, a sheet of atoms in a square lattice, each atom linked to its four closest neighbors by four springs oriented along the two perpendicular axes. (a) What would you expect the molar heat capacity to be at very low temperatures and at very high temperatures? (b) What quantity would determine, roughly, the line between low and high?

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