Chapter 9: Q83E (page 409)
From equation (9-51), show that the specific heat (per mole) of a crystalline solid varies as for .
Short Answer
Specific heat (per mole) of a crystalline solid varies as for .
Chapter 9: Q83E (page 409)
From equation (9-51), show that the specific heat (per mole) of a crystalline solid varies as for .
Specific heat (per mole) of a crystalline solid varies as for .
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Get started for freeExercise 67 calculates the minimum total energy in a system of spin fermions and is applicable to conduction electrons in a metal. The average particle energy is the total energy divided by the number of particles .Show that the average particle energy of a conduction electron at low temperature is . This form is convenient, being rather simple, and it can easily he put in terms of and via equation .
Discusses the energy balance in a white dwarf. The tendency to contract due to gravitational attraction is balanced by a kind of incompressibility of the electrons due to the exclusion principle.
(a) Matter contains protons and neutrons, which are also fanions. Why do the electrons become a hindrance to compression before the protons and neutrons do?
(b) Stars several times our Sun's mass has sufficient gravitational potential energy to collapse further than a white dwarf; they can force essentially all their matter to become neutrons (formed when electrons and protons combine). When they cool off, an energy balance is reached like that in the white dwarf but with the neutrons filling the role of the incompressible fermions. The result is a neutron star. Repeat the process of Exercise 89. but assume a body consisting solely of neutrons. Show that the equilibrium radius is given by
(c) Show that the radius of a neutron star whose mass is twice that of our Sun is only about .
Copper has a density of, and no photoelectrons are ejected from it if the wavelength of the incident light is greater than(in the ultraviolet range). How deep is the well in which its conduction electrons--one per atom-are bound?
Show that in the limit. Equation (9.15) becomes (9.28).
Verify that the probabilities shown in Table 9.1 for four distinguishable oscillators sharing energy agree with the exact probabilities given by equation (9-9).
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