Question: Show that the normalization constant 15/32π given in Table 7.3 for the angular parts of the l=2,ml=±2 wave function is correct.

Short Answer

Expert verified

Answer

It has been proved that the normalization for the case l=2,ml=±2is correct.

Step by step solution

01

Given data

Thewavefunctioncorrespondingtol,ml=2,±2is,Θl,mlθΦmlϕ=1532πsin2θe±2iϕ

02

Normalization

TheangularpartoftheHydrogenatomwavefunctionshouldsatisfytheconditionas:0π{Θl,mlθ}22πsinθdθ=1

03

Determining whether the given normalization constant is correct

In the given wave function,

Θl,mlθ=1532πsin2θ

Check equation (I) as,

=1532π×2π0πsin5θdθ=15160πsin4θsinθdθ=15160πsin2θ2sinθdθ=15160π1-cos2θ2sinθdθ

Let us assume,

cosθ=z-sinθdθ=dz

Then the integral becomes,

=15161-11-z22-dz=1516-111+z4-2z2dz=1516z+z55-2z33-11=15162+25-43=1

Thus the normalization is correct.

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Verify that equation (4-19) follows from (4-16) and (4-18).

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(b) In which of the following ways does this state differ from its parts (i.e., ψ2,1,+1and ψ2,1,-1) and from the 2pz state: Energy? Radial dependence of its probability density? Angular dependence of its probability density?

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