From equations (6-23) and (6-29) obtain the dispersion coefficient for matter waves (in vacuum), then show that probability density (6-35) follows from (6-28)

Short Answer

Expert verified

The dispersion coefficient of matter waves in vacuum is hmand it is verified that probability density is followed from equation (6-28)

Step by step solution

01

Definition of dispersion relation

The relation between angular frequency and the wave number of matter wave is termed as the Dispersion relation

02

Determination of the value of coefficient of dispersion

Write the expression of matter wave dispersion relation from (6–23).

ω(k)=hk22m

Here, ωis angular frequency of matter wave, k is wave number and m is mass of corresponding particle.

Write the expression of coefficient of dispersion from (6–29).

D=d2ω(k)dk2

Substitute hk22mfor ω(k)in the above expression.

D=d2hk22mdk2=hm

03

Verification of the given condition

Write the expression of probability density from (6–28).

|Ψ(x,t)|2=c21+D2t24ε412exp-(x-st)22ε21+D2t24ε4

Here, C is amplitude of wave function and t is any arbitrary time.

Substitutehmfor D in above expression.

|Ψ(x,t)|2=c21+hm2t24ε412exp-(x-st)22ε21+hm2t24ε4=C21+h2t24m2ε41/2exp-(x-st)22ε21+h2t24m2ε4

It can be observed that the above expression resembles equation (6-35) therefore it is verified that it follows from equation (6-28).

Therefore, the dispersion coefficient of matter waves in vacuum is hmand it is verified that probability density is followed from equation (6–28).

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