We analyze the photoelectric effect using photon energy alone. Why isn't the photon momentum a consideration? (It may help to reread the discussion of momentum and energy in connection with pair production.)

Short Answer

Expert verified

The photon's momentum is not considered as it is transferred to the metal atoms and has to be taken into account while conserving total momentum.

Step by step solution

01

Concept Introduction

When a light source having energy greater than the work function of the metal surface shines on the metal surface, electrons are emitted from the metal surface. This phenomenon is known as the photoelectric effect. The photon interacts with the metal atoms exchanging momentum and energy.

02

Photoelectric effect

In the photoelectric effect, the photon's kinetic energy is slightly altered as the mass of the interacting atoms is quite large compared to an incoming photon. So, the minute change in kinetic energy of a photon is neglected and energy conservation works perfectly.

03

Conservation of momentum

Due to the presence of metal atoms, most of the photon's momentum gets transferred to the interacting metal atoms. So, the conservation of total momentum cannot be taken without considering the momentum of the metal atoms.

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Most popular questions from this chapter

A photon and an object of mass m have the same momentum p.

  1. Assuming that the massive object is moving slowly, so that non-relativistic formulas are valid, find in terms of m , p and c the ratio of the massive object’s kinetic energy, and argue that it is small.
  2. Find the ratio found in part (a), but using relativistically correct fomulas for the massive object. (Note: E2=p2c2+m2c4may be helpful.)
  3. Show that the low-speed limit of the ratio of part (b) agrees with part (a) and that the high-speed limit is 1.
  4. Show that at very high speed, the kinetic energy of a massive object approaches .

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