According to Wien's Law, the wavelengthλmax of maximum thermal emission of electromagnetic energy from a body of temperature Tobeys

localid="1660036169367" λmaxT=2.898×10-3m·K

Show that this law follows from the spectral energy density obtained in Exercise 13. Obtain an expression that, when solved, would yield the wavelength at which this function is maximum. The transcendental equation cannot be solved exactly, so it is enough to show thatlocalid="1660036173306" λ=2.898×10-3m·KTsolves it to a reasonable degree of precision.

Short Answer

Expert verified

The Wien's law, λmaxT=2.9×10-3mK.

Step by step solution

01

Given data

Wein’s Law and spectral energy density.

02

Formula used

Planck's formula in terms of wavelength

dUdλ=8πVhc(ehc/λkBT-1)×1λ5

Some useful values:

h=6.63×10-34J·s,kB=1.38×10-23J·K-1,andc=3×108m·s-1

03

Calculation using Planck’s formula

To find the peak of the blackbody radiation, the derivative should be equal to ' 0 '. At that point, the value of λwill correspond to the maximum. The constant term will not affect to the peak of the radiation

ddλ8πVhcehc/λkBT-1×1λ5=0

Solving the above will give,

Therefore,

xexex-1-5=0(x-5)ex+5=0

Solving this equation, x=4.9651

Therefore,

λmaxT=hcxkB=6.63×10-34J·s×3×108m·s-14.9651×1.38×10-23J·K-1=2.9×10-3m·K

04

Conclusion

The Wien's law, λmaxT=2.9×10-3mK.

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