From equations (3-4) to (3-6) obtain equations (3.8). It is easiest to start by eliminating φ between equations (3-4) and (3-5) using cos2φ+sin2φ = 1 The electron speed u may then be eliminated between the remaining equations.

Short Answer

Expert verified

Using the given equations, the following can be obtained is λ'-λ=hmec1-cosθ.

Step by step solution

01

Given data

hλ=hλ'cosθ+γumeucosϕ..(1)0=hλ'sinθ-γumeusinϕ..(2)hcλ-mec2=hcλ'+γumec2..(3)

02

Concept  used

Einstein's mass-energy equivalence relation can be expressed as,

E = mc2

03

Use the equations and solve

Rearranging the above equations (1 and 2) will give:

γumeucosϕ=hλ-hλ'cosθγumeusinϕ=hλ'sinθ

Squaring both will give:

γumeu2cos2ϕ=hλ-hλ'cosθ2γumeu2sin2ϕ=hλ'sinθ2

Adding both equations will lead to:

γumeu2=hλ2-2h2λλ'cosθ+hλ'2…..(4)

The Square of equation 3 will give

γumeu2=hλ2+hλ2-2h2λλ'+2mechλ-hλ'+me2c2…..(5)

04

Subtract equation 5 from equation 4

Simplify further,

me2γu2c2-γu2c2=-2h2λλ'1-cosθ+2mechλ'-hλ+mec22h2λλ'1-cosθ=2mechλ'-hλhλλ'1-cosθ=mec1λ'-1λλ-λ'=hmec1-cosθ

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