A beam of electrons strikes a crystal at an angleθwith the atomic planes, reflects of many atomic planes below the surface, and then passes into a detector also making angleθwith the atomic planes. (a) If the minimumθgiving constructive interference is.35° What is the ratioλ/d, Where is the spacing between atomic planes? (b) At what other angles, if any, would constructive interference occur?

Short Answer

Expert verified

(a) The ratio of given minimum angle isλd=1.15.

(b) Here can notbe considered as2 . So this is an invalid value of thesinθ.As a result, the only integer that exists ism=1 .This is the smallest angle at which constructive interference was detected. As a result, constructive interference is not visible from any other angles.

Step by step solution

01

Given data.

(a)

The angle of constructive interferenceθmin=35°.

02

Bragg's equation.

When there is constructive interference, Bragg's equation can be used to describe the relationship between the quantities.

2dsinθ=mλ………………(1)

03

Ratio between wavelength and spacing

Using equation(1).

2dsinθ=mλ2sinθ=dλd=2sinθm

θminis the minimum angle for the constructive interference, som=1.

λd=2×sinθm=2×sin(35°)1=1.15

Therefore the ratio ofλd is 1.15in the spacing between the atomic planes.

04

Condition for the constructive interference(b)

From Equation(1)the minimum value forsinθis1.

So,

2dsinθ=mλsinθ=2d12dm2λd

Insertλd=1.15

m2λd21.15=1.74

Here m can notbe considered as 2.So this is an invalid value of the.sinθ

As a result, the only integer that exists ism=1 .

This is the smallest angle at which constructive interference was detected. As a result, constructive interference is not visible from any other angles.

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