Determine the Compton wavelength of the electron, defined to be the wavelength it would have if its momentum weremec.

Short Answer

Expert verified

Compton Wavelength of the electron

λ=2.43×10-12m

Step by step solution

01

Step 1:Given and unknowns.

me=9.1×10-31kg--the electron's mass

p=mec--the electron's momentum

02

Concept Introduction

The following equation can be used to describe the de Broglie wavelength.

p=hλ…………………..(1)

03

Expression of wavelength.

Know that the electron's momentum isp=mec .

Get the wavelength expression as follows

p=hλ

p=mec

mec=hλ

λ=hmec

04

Compton Wavelength of Electron.

Using the wavelength's derived expression, Obtainλas:

λ=hmec=6.626×10-34Js(9.1×10-31kg)×(3.0×108m/s)=2.43×10-12m λ=hmec=6.626×10-34Js(9.1×10-31kg)×(3.0×108m/s)=2.43×10-12m

The Compton Wavelength of the electron isλ=2.43×10-12m .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A particle is “thermal” if it is in equilibrium with its surroundings – its average kinetic energy would be32kBT. Show that the wavelength of a thermal particle is given by

λ=h3mkBT

The energy of a particle of massbound by an unusual spring isβ/2m+bx4.

(a) Classically. it can have zero energy. Quantum mechanically, however, though bothx andpare "on average" zero, its energy cannot be zero. Why?

(b) Roughly speaking.Δxis a typical value of the particle's position. Making a reasonable assumption about a typical value of its momentum, find the particle's minimum possible energy.

Roughly speaking for what range of wavelengths would we need to treat an electron relativistically, and what would be the corresponding range of accelerating potentials? Explain your assumptions.

The proton and electron had been identified by 1920, but the neutron wasn't found until 1932. Meanwhile, the atom was a mystery. Helium, for example, has a mass about four times the proton mass but a charge only twice that of the proton. Of course, we now know that its nucleus is two protons and two neutrons of about the same mass. But before the neutron's discovery, it was suggested that the nucleus contained four protons plus two electrons, accounting for the mass (electrons are "light") and the total charge. Quantum mechanics makes this hypothesis untenable. A confined electron is a standing wave. The fundamental standing wave on a string satisfies L=12λ, and the "length of the string" in the nucleus is its diameter.2Rnuc, so, the electron's wavelength could be no longer than about4RmucAssuming a typical nuclear radius of 4×10-15m determine the kinetic energy of an electron standing wave continued in the nucleus. (Is it moving "slow" or "fast"?) The charge of a typical nucleus is +20e , so the electrostatic potential energy of an electron at its edge would be-(1/2πε0)20e2/Rnuc(it would be slightly lower at the center). To escape. the electron needs enough energy to get far away, where the potential energy is 0. Show that it definitely would escape.

Determine the momenta that can never be measured when a particle has a wave function.

ψ(x)={C;|x|+12w0;|x|>12w}

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free