Roughly speaking for what range of wavelengths would we need to treat an electron relativistically, and what would be the corresponding range of accelerating potentials? Explain your assumptions.

Short Answer

Expert verified

Rane of Wavelength and Range of Accelerating potentials:

λ2.43×10-11 m, and V2.556 keV

Step by step solution

01

Step 1:Concept Introduction

The wavelength of any moving charged particle is given by the,

λ=h2mqV…………………..(1)

Where m, q, and V are the mass, charge, and applied potential difference.

02

Step 2:Formula.

λ=hp=hmevλ=6.63×10-34Js(9.1×10-31 kg)×(3×107 m/s)λ=2.43×10-11m

03

Relativistic Treatment.

Relativistic treatment is required for wavelengths equal to or smaller than this value.

V=h22me2V=(6.63×10-34Js)22×(9.1×10-31kg)×(1.6×10-19 C)×(2.43×10-11 m)2V=2.556 keV

Relativistic therapy will be required if the potential is equal to or greater than this value.

λ2.43×10-11 m, and V2.556 keV

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