A beam of electrons of 25 eVkinetic energy is directed at a single slip of 2.0 μm width, then detected at a screen 4m beyond the slit. How far from a point directly in the line of the beam is the first location where no electrons are ever detected?

Short Answer

Expert verified

The line of the beam is detected aty=0.25mm

Step by step solution

01

 Step 1: Given information

The potential difference for the electron beam is25 eV

The slit's width=2 μm

The space between the screen and the slit=4 m

02

Concept Introduction

The wavelength of any moving charged particle is given by the,

λ=h2mqV…………………..(1)

Where m, q, and V are the mass, charge, and applied potential difference.

03

Calculation of the wavelength

Substitute the given information in equation (1) to obtain the wavelength such that,

λ=6.63×1034Js2×(9.1×1031kg)×(1.6×1019C)×(25V)=2.46×1010m

04

 Another formula substituting.

mλ=ωsinθ12λ=ω×yD12×2.46×10-10m=2.0×106m×y4my=0.25mm

Therefore, the result is y=0.25 mm.

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