Nonrelativistically, the energyEof a free massive particle is just kinetic energy, and its momentumis. of course,mv. Combining these with fundamental relationships (4-4) and (4-5), derive a formula relating (a) particle momentumto matter-wave frequency fand (b) particle energyEto the wavelengthλof a matter wave.

Short Answer

Expert verified

a) The derivative formula by relating particle momentum to matter-wave frequency is p=2mhf.

b) The derivative formula by relating particle energy to the wavelength of a matter wave is E=h22mλ2

Step by step solution

01

Relation of wave-particle momentum and energy.

The following equations describe the fundamental wave-particle momentum andenergy relationships, respectively.

p=hλ…………………(1)

E=hf……………….. (2)

02

Relationship between momentum and frequency.

The relationship between momentum and frequency is described by an equation.

The energy can be expressed asE=p22m

Putting this expression and equation(2), we have:

E=p22m

E=hf

p22m=hf

03

Derivative equation for  

(a)

The equation forpis then as follows:

p22m=hf

p2=2mhf

p=2mhf

As a result, the equation for momentum and frequency is p=2mhf.

04

Relation between energy and wavelength.

After that, we create an equation that connects energy and wavelength.

We know that,E=p22m.

Now, relate this to the equation (1), then the equation is as follows:

E=p22m

p=hλ

.

05

Derivative equation for energy-wavelength(b)

The equation forEis then as follows:

E=h22mλ2

As a result, the energy-wavelength equation is E=h22mλ2

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