In Exercise 45, the case is made that the position uncertainty for a typical macroscopic object is generally so much smaller than its actual physical dimensions that applying the uncertainty principle would be absurd. Here we gain same idea of how small an object would have♦ to be before quantum mechanics might rear its head. The density of aluminum is 2.7×103kg/m3, is typical of solids and liquids around us. Suppose we could narrow down the velocity of an aluminum sphere to within an uncertainty of1μmper decade. How small would it have to be for its position uncertainty to be at least as large as110%of its radius?

Short Answer

Expert verified

The radius of the microscopic object to obtain the required uncertainty in position is r105m.

Step by step solution

01

Concept of Heisenberg's Uncertainty Principle. 

The expression for density is given by,

D=m43πR3m=43πR3D

Here, mis mass, Dis the density and Ris the radius

The expression for Heisenberg’s uncertainty principle in terms of mass and velocity is given by,

mΔvxΔxh2(43πR3D)ΔvxΔxh28πDR3ΔvxΔx3hΔx3h8πDR3Δvx

The expression for uncertainty in position as a fraction of radius is given by,

ΔxRk(3δ8eDR3Δvx)Rk3h8πDR4ΔvxkR3h8πkDΔvx

Here, Δvxthe change in velocity, Dis the density, h is Planck’s constant, Δx

is the uncertainty in position and Ris the radius.

02

Use Heisenberg’s Uncertainty Principle for calculation. 

Consider volume for the object isV=43πr5and the uncertainty in velocity, consequently the momentum, is known.

Substitute given values we can get an estimate of the value ofr(noteΔx=0.10%of r).

ΔxΔp2ΔxmΔv2

Here,Δxis the uncertainty in position, Δpis uncertainty in momentum, m is the mass and Δvis velocity change and is Planck’s constant.

Δx=0.001r,  m=ρVm=ρ×43πr3

Now substitute the value in formula

ΔxmΔv20.001r×ρ×43πr3Δv2

Solve further as:

r2×0.001×ρ×43π×Δv4r=1.054×1034kgm2s2×0.001×2.7×103kg/m3×43π×106m10×365×24×60×60s4r=1.469×10204mr105m

Thus, the radius of the microscopic object to obtain the required uncertainty in position isr105m .

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Most popular questions from this chapter

According to the energy-time uncertainty principle, the lifetimelof a state and the uncertaintyEin its energy are invertible proportional. Hydrogen's red spectral line is the result of an electron making a transition "downward" frum a quantum state whose lifetime is about10-8s.

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